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Thepotemich [5.8K]
3 years ago
11

Somebody please help

Mathematics
1 answer:
DENIUS [597]3 years ago
8 0
What you want to do, is isolate the y by itself to rewrite the equation as y=mx+b. So when you move the 5x over the equation looks like this -6y=-5x+30. Then you divide the -5x+30 by -6 to isolate the y. Thus making the equation y=5/6x-5. And since there is only one answer with the y-intercept as (0,-5); The answer is A.
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Availability is the most important consideration for designing servers, followed closely by scalability and throughput. a. [10]&
SashulF [63]

Answer:

a) Mean Time to failure (MTTF) = (10^7) hours

b) Availability of the system = 1

c) Mean Time to failure for 1000 processors = 10^4 hours.

Step-by-step explanation:

a) Failures in time (FIT) is traditionally reported as failure Per billion hours Of Operation.

1 billion = (10^9)

FIT = 100/(10^9) = 10^-7

MTTF = 1/FIT = 1/(10^-7) = (10^7) hours

b) Availability of the system = MTTF/(MTTF + MTTR)

MTTR = mean time to repair = 24hours

Availability of the system = (10^7)/((10^7) + 24) = 0.9999 = 1

c) FIT = 1000 (processors) × 100 (FIT per processor) = (10^5) per billion hours of operations = (10^5)/(10^9) = 10^-4

MTTF = 1/FIT = 1/(10^-4) = (10^4) hours

QED!!

7 0
3 years ago
What time is it 120 minutes after midday?​
coldgirl [10]
Midday is 12pm so you add whatever hours to that. Which is 1:20pm after midday (12pm)
7 0
3 years ago
Approximately 14 percent of the population of Arizona is 65 years or older. A random sample of five persons from this population
Andreas93 [3]

Answer:

A)0.8533

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they are 65 or older, or they are not. The probability of a person being 65 or older is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

14 percent of the population of Arizona is 65 years or older.

This means that p = 0.14

A random sample of five persons from this population is taken.

This means that n = 5

The probability that less than 2 of the 5 are 65 years or older is :

P(X < 2) = P(X = 0) + P(X = 1)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(0.14)^{0}.(0.86)^{5} = 0.4704

P(X = 1) = C_{5,1}.(0.14)^{1}.(0.86)^{4} = 0.3829

P(X < 2) = P(X = 0) + P(X = 1) = 0.4704 + 0.3829 = 0.8533

So the correct answer is:

A)0.8533

3 0
3 years ago
If 20+20 is 40 percent what is 20 of half percent.
hichkok12 [17]
I don’t know if this is correct: 40%
3 0
3 years ago
Read 2 more answers
The weight distribution of parcels sent in a certain manner is normal with mean value 17 lb and standard deviation 3.3 lb. The p
Yakvenalex [24]

Answer: The value of c would be 26.514 lb.

Step-by-step explanation:

Since we have given that

Mean = 17 lb

Standard deviation = 3.3 lb

At 99%  level of significance, z = 2.58

So, it becomes,

Z=\dfrac{X-\mu}{\sigma}\\\\2.58=\dfrac{X-17}{3.3}\\\\2.58\times 3.3=X-17\\\\8.514+17=X\\\\X=25.514

So, the weight c would be

c=25.514+1\\\\c=26.514

Hence, the value of c would be 26.514 lb.

7 0
3 years ago
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