<h3><u>given</u><u>:</u></h3>
base= 25mm
height= 28mm
<h3><u>to</u><u> </u><u>find</u><u>:</u></h3>
the volume of the pyramid.
<h3><u>solution</u><u>:</u></h3>
v= a^2 h/3
v= 25^2 28/3
v= 5833.33333
v= 5833.3mm^3
Answer:
15.71 ft
Step-by-step explanation:
Given that:
width of the circular track = 2.5ft
Suppose the radius of the inner circle is 57 ft since it is not given
Then the radius of the outer circle = (2.5 + 57) ft = 59.5 ft
The circumference of a circle = 2πr
For inner circle now, the circumference = 2 × π × 57 ft
For inner circle now, the circumference = 358.14 ft
For the outer circle, the circumference = 2 × π × 59.5 ft
For the outer circle, the circumference = 373.85 ft
The difference between the circumference of the outer wheel from the inner wheel shows how farther does a wheel on the outer rail travel than a wheel on the inner rail of the track in one turn
∴
= ( 373.85 - 358.14 ) ft
= 15.71 ft
It will take 12 truckloads to fill up one warehouse. Hope this helps.
The sector area and the arc length are 34.92 square inches and 13.97 inches, respectively
<h3>How to find a sector area, and arc length?</h3>
For a sector that has a central angle of θ, and a radius of r;
The sector area, and the arc length are:
--- sector area
---- arc length
<h3>How to find the given sector area, and arc length?</h3>
Here, the given parameters are:
Central angle, θ = 160
Radius, r = 5 inches
The sector area is
So, we have:
Evaluate
A = 34.92
The arc length is:
So, we have:
L = 13.97
Hence, the sector area and the arc length are 34.92 square inches and 13.97 inches, respectively
Read more about sector area and arc length at:
brainly.com/question/2005046
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