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ddd [48]
3 years ago
11

Draw two different perimeters of a rectangle with an area of 14 units. Name their dimensions.

Mathematics
1 answer:
Alenkasestr [34]3 years ago
8 0
1:
Length: 7
Width:2
Perimeter: 18

2:
Length: 5
Width: 2.8
Perimeter: 15.6
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What are the solutions of each equation? <br> a. x2 + 4 = 4<br> b. x2 + 16 = 0<br> c. x2 − 49 = 0
OLga [1]

Answer:

a. x=0

b x=-8

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Step-by-step explanation:

a. x2+4=4

subtract 4 from both sides

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multiply

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divide by 2

x=0

b x2 + 16 = 0

multiply

2x+16=0

subtract both sides by 16

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divide by 2

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c  x2 − 49 = 0

multiply

2x-49=0

add 49 to both sides

2x=49

divide both sides by 2

x=49/2

5 0
3 years ago
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Schach [20]

Answer:

From given, we have,

Paul says he is 16 inches shorter than 1 1/2 times Theresa's height.  

Steve says he's 6 inches shorter than 1 1/3 times Theresa's height.

Let the height of Theresa be "x" inches.

So, we get,

For Paul, 1 1/2 x - 16 = T

⇒ 3/2 x - 16 = T ......(1)

For Steve, 1 1/3 x - 6 = T

⇒ 4/3 x - 6 = T .........(2)

equating  equations (1) and (2), we get,

3/2 x - 16 =  4/3 x - 6

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-10 = (8 - 9)/6 x

-60 = -x

x = 60 inches.

Therefore, Theresa is 60 inches tall.

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3 years ago
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Step-by-step explanation:

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3 years ago
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tia_tia [17]
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3 years ago
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