1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
cluponka [151]
3 years ago
11

Can someone help me with this

Mathematics
1 answer:
gogolik [260]3 years ago
3 0

Answer:

You picked the right answer- it's the top one. Only one that makes sense

Step-by-step explanation:

You might be interested in
6/7 as a fraction divided by a whole of 12
ValentinkaMS [17]

Answer:

<u>(1/14)</u>

Step-by-step explanation:

(6/7)/(12)              <u>6/7 as a fraction divided by a whole of 12</u>

(6/7)/(12/1)

(6/7)*(1/12)

(1/7)*(1/2)

(1/14)

4 0
2 years ago
Read 2 more answers
Mary has 40% fewer marbles than Jolie. If they combine all their marbles in a single bag, what percent of the marbles in the bag
dedylja [7]
The easiest way to do this would be to imagine that Jolie has 100 marbles. If Mary has 40% fewer, that means she has 60 marbles. Then if they combine all their marbles into a single bag, they will have 160 marbles, of which 100 are Jolie's. So the % that is Jolie's is 100/160 = 0.625 = 62.5%.
4 0
3 years ago
What is the term, coefficient, constant, and factor of 1/2(base1 + base2)h? (Formula used to find area of trapezoid)
vovangra [49]

Answer:

i. Term = \frac{b_{1}h }{2} + \frac{b_{2}h }{2}

ii. Coefficient = \frac{1}{2}

iii. Constant = \frac{1}{2}

iv. Factor = \frac{h}{2}

Step-by-step explanation:

A trapezoid is a quadrilateral which has its base parallel to the opposite side. It's area can be determined by;

Area of trapezium = \frac{1}{2} (b_{1} + b_{2})h

Where b_{1} is the measure of length of its fist base,  b_{2} is the measure of its second base and h is its height.

Considering the given question,

Term = \frac{b_{1}h }{2} + \frac{b_{2}h }{2}

Coefficient = \frac{1}{2}

Constant = \frac{1}{2}

Factor = \frac{h}{2}

6 0
3 years ago
)) In a right triangle, a and b are the lengths of the legs and c is the length of the
kondor19780726 [428]

Answer:

5.66 inches

Step-by-step explanation:

{a}^{2}  +  {b }^{2}   =   {c}^{2}

a² + 7² = 9²

a² + 49 = 81

a² + 49 - 49 = 81 - 49

a² = 32

a = square root of 32

a = 5.6568 or 5.66 inches

I used the Pythagorean Theorem to solve this.

7 0
3 years ago
Read 2 more answers
If the ratio of y to x is equal to 3 and the sum of y and x is 80, what is value of y
Rus_ich [418]

Answer:

y = 60

Step-by-step explanation:

<h3>Step 1: Make sense of the given</h3>

"The ratio of y to x is 3"

This means that, y\div x=3

"The sum of y and x is 80"

This means,  x+y=80

<h3>Step 2: Make use of the facts</h3>

If y\div x=3, then y = (3*x).

We can plug this into the other equation by substitution:

x + (3 * x)=80

This simplifies to:

4x = 80

Which we can solve out and get:
x=20.

<h3>Step 3: Plug and Chug</h3>

We solved for x, but we need the value of y.

So, we go back to the equation we first derived: "y = (3*x)".

And now we substitute the value of x, into this.

y = (3 * (20))

By solving this out, we get:
y=60

So, the value of y is 60.

3 0
2 years ago
Other questions:
  • What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form?
    12·1 answer
  • Help me pleasssseeeee! THANK YOU
    9·2 answers
  • There are 9 students in a class: 5 boys and 4 girls. If the teacher picks a group of 4 at random, what is the probability that e
    7·1 answer
  • Which correctly shows how to use the GCF and the distributive property to find an expression equivalent to 24 + 44?
    9·2 answers
  • How do I solve these?
    12·1 answer
  • (2-7m^6)^2<br><br><br> i dont know this
    6·1 answer
  • Independent and dependent events pls help 49 points
    14·1 answer
  • Solve for x in the picture below
    15·1 answer
  • Please help only answer if you're sure it right​
    13·2 answers
  • Type the correct answer in each box.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!