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navik [9.2K]
3 years ago
11

How can I find answer to this problem?

Mathematics
1 answer:
nekit [7.7K]3 years ago
6 0

Answer: The answer is B) y > 4.

Step-by-step explanation: When you transfer the -1 to the y side you add it and pick which number adds to the sum of 5

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The base of the pyramid is a square. what is the volume of the pyramid. enter your answer in the box.
Ugo [173]

Answer:

The volume of the pyramid is 672\ cm^{3}

Step-by-step explanation:

we know that

The volume of the pyramid of the figure is equal to

V=\frac{1}{3}b^{2}h

we have

b=12\ cm

h=14\ cm ----> the height must be perpendicular to the base

substitute

V=\frac{1}{3}(12^{2})(14)=672\ cm^{3}

7 0
3 years ago
What is the perimeter of the truss in feet?
Zanzabum

I think the truss is just one of those triangles whose sides are 3ft, 3ft, 3ft so its perimeter is


Answer: 9 feet



5 0
4 years ago
Cuanto es 12 + 1? Porfavor es para mi tarea de matemáticas.
Nastasia [14]

Answer:

13

is your answer

Step-by-step explanation:

6 0
3 years ago
Need help asap please​
victus00 [196]

Answer:

z=3.3 repeating

Step-by-step explanation:

Move all terms that don't contain  z  to the right side and solve.

7 0
3 years ago
Simplify (12a5−6a−10a3)−(10a−2a5−14a4) . Write the answer in standard form
almond37 [142]

Answer:

=14a^5+14a^4-10a^3-16a

Step-by-step explanation:

\left(12a^5-6a-10a^3\right)-\left(10a-2a^5-14a^4\right)\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\=12a^5-6a-10a^3-\left(10a-2a^5-14a^4\right)\\-\left(10a-2a^5-14a^4\right):\quad -10a+2a^5+14a^4\\-\left(10a-2a^5-14a^4\right)\\\mathrm{Distribute\:parentheses}\\=-\left(10a\right)-\left(-2a^5\right)-\left(-14a^4\right)\\Apply\:minus-plus\:rules\\-\left(-a\right)=a,\:\:\:-\left(a\right)=-a\\=-10a+2a^5+14a^4\\=12a^5-6a-10a^3-10a+2a^5+14a^4

\mathrm{Simplify}\:12a^5-6a-10a^3-10a+2a^5+14a^4:\quad 14a^5+14a^4-10a^3-16a12a^5-6a-10a^3-10a+2a^5+14a^4\\Group\:like\:terms\\=12a^5+2a^5+14a^4-10a^3-6a-10a\\\mathrm{Add\:similar\:elements:}\:12a^5+2a^5=14a^5\\=14a^5+14a^4-10a^3-6a-10a\\\mathrm{Add\:similar\:elements:}\:-6a-10a=-16a\\=14a^5+14a^4-10a^3-16a

4 0
3 years ago
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