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N76 [4]
4 years ago
7

The position of an object moving along a straight line for

Mathematics
1 answer:
NikAS [45]4 years ago
3 0

Answer:

at 2/3 seconds

Step-by-step explanation:

S1(t) = t³ + 2

Average speed, dS1/dt = 3t²

S2(t) = t²

Average speed, dS2/dt = 2t

The distance between the objects is

dS1/dt - dS2/dt

= 3t² - 2t

The time the distance between the two object is at minimum is when the distance is 0

That is, when

3t² - 2t = 0

t(3t - 2) = 0

t = 0 or 3t - 2 = 0

t = 0 or t = 2/3

You might be interested in
What are Absolute Value Equations​
nikdorinn [45]

Absolute Value Equations are equations that look like this:

I x + 5 I = 15

They have 2 solutions almost all the time. To solve this equation we do this:

x+5=15      x+5=-15

Then you solve them:

x+5=15      x+5=-15

x=15-5       x=-15-5

x=10           x=-20

The solutions would be x=10 and x=-20 .

In some cases, you only have one solution:

I x + 5 I = 0

0 cannot be negative, so we only have one equation to solve:

x+5=0

x=0-5

x=-5

The one solution would be x=-5 .

In some OTHER cases, you have no solution. This happens when the absolute value equation equals to a negative number:

I x + 5 I =-10

Absolute value solutions are always going to end up positive because absolute value turns the number, negative or positive, into a positive.

5 0
3 years ago
Determine if the given function can be extended to a continuous function at xequals0. If​ so, approximate the extended​ function
Akimi4 [234]

Complete Question

The  complete question is shown on the first uploaded image

Answer:

The correct option is  A

Step-by-step explanation:

Now  from the question we are given the function

        f(x) =  \frac{10^{2 x} -4}{x}

Now  as  \lim_{x \to 0} [f(x) ] =  \frac{10^{2*0} -4 }{0}

       =>    \lim_{x \to 0} [f(x) ] = - \infty

This  implies that as x\to 0 the function f(x)  \to -\infty which means that at  x = 0  the function is not continuous  

3 0
4 years ago
Miles is planning to spend 2/3 as many hours Bicycling this week as he did last week is Miles going to spend more hours were few
Firlakuza [10]

Answer: Yes, He bicycled fewer in this week than last week.

Step-by-step explanation:

Let he bicycled x hours in the last week,

Then, According to the question,

\text{ He bicycled in this week} = \frac{2}{3} \text{ of the hours he bicycled last week} = \frac{2x}{3}

\text{ Since, }1 > \frac{2}{3}

\implies x > \frac{2x}{3}

\text{ He bicycled in the last week} > \text{ he bicycled in this week}

Hence, He bicycled fewer in this week than last week.


3 0
3 years ago
2593 ÷6 use compatible numbers to do estimate
Dafna1 [17]
I miss compatible numbers round 2593 too 2,600 then round 6 to ten and your answer is 260 hope this helps:D
6 0
3 years ago
Read 2 more answers
Solve for x.<br><br> 7x=2x−35<br><br><br> x = 7<br><br> x = 5<br><br> x=−5​<br><br> x=−7
Svet_ta [14]
It’s -7
Because you subtract -2 with 7 and it equals 5x=-35 and then u divide it and it equals -7
8 0
4 years ago
Read 2 more answers
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