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N76 [4]
4 years ago
7

The position of an object moving along a straight line for

Mathematics
1 answer:
NikAS [45]4 years ago
3 0

Answer:

at 2/3 seconds

Step-by-step explanation:

S1(t) = t³ + 2

Average speed, dS1/dt = 3t²

S2(t) = t²

Average speed, dS2/dt = 2t

The distance between the objects is

dS1/dt - dS2/dt

= 3t² - 2t

The time the distance between the two object is at minimum is when the distance is 0

That is, when

3t² - 2t = 0

t(3t - 2) = 0

t = 0 or 3t - 2 = 0

t = 0 or t = 2/3

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Answer:

a = 7

Step-by-step explanation:

I think, what you need to do, is first understand how to find the mean of anything: It's quite simple, actually, just add up all the numbers, then divide that number by the number of numbers. So, let's put it in perspective:

10, 3, 4, a, 6, 9, 10

7 is the mean. 7 is the number of numbers.

If, to find the mean is: 10 + 3 + 4 + a + 6 + 9 + 10= 7a ÷ 7, then: 10 +3 + 4+ 6 + 9 +10= 42

42 plus what divided by 7 is the question now.

42 + a ÷  7= 7

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3 years ago
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Aloiza [94]

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Step-by-step explanation:

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3 years ago
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I need help I don’t know how that’s not right.
Leviafan [203]

Answer: v=-81.92

Step-by-step explanation:

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anastassius [24]

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The only way to have the same number of birds (1) in all cages is to have 60 cages, 42 of which have 1 parakeet, and 18 of which have 1 canary.

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If more than 1 of each kind of bird can be put in the cage, the collection of birds could be put into 6 cages, each of which would be home to 7 parakeets and 3 canaries.

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