B. (k+10f)(k-5f) you can tell in 2 ways. 1. if the second sign is neg then the signs in the factors are going to be one neg and one positive so that knocks out C and D. Then you look at the second term and since the 5 is positive then the 10 has to be positive so you end up with a positive 5kf.
The second way is to FOIL them out. When you check B you get
![k^{2} -5kf+10kf- 50f^{2}](https://tex.z-dn.net/?f=%20k%5E%7B2%7D%20-5kf%2B10kf-%2050f%5E%7B2%7D%20)
combine your like terms and you have your original expression of
![k^{2} +5kf-50 f^{2}](https://tex.z-dn.net/?f=%20k%5E%7B2%7D%20%2B5kf-50%20f%5E%7B2%7D%20)
Hope that helps
Answer:
The answer to this question is dilating the figure by a scale factor of one half.
Step-by-step explanation:
Part A:
So the height is going to be x when you fold the sides up. So that's one part of the volume but for the width it was going to be 4 but since two corners were cut out with the length x the new width is going to be (4-2x). The same thing applies for the length which should be 8 inches but since two corners were removed with the length x it's now (8-2x)
v = x(4-2x)(8-2x)
Part B:
The volume can be graphed although there must be a domain restriction since the height, width, or length cannot be negative. So let's look at each part of the equation
so for the x in front it must be greater than 0 to make sense
for the (4-2x), the x must be less than 2 or else the width is negative.
for the (8-2x) the x must be less than 4 or else the length is negative
so the domain is going to be restricted to 0 < x < 2 so all the dimensions are greater than 0
By using a graphing calculator you can see the maximum of the given equation with the domain restrictions is 0.845 which gives a volume of 12.317
For part a it’s sal will leave a $20 tip for part b sals food is $78.22 including tax and tip
Answer:-8/3
Step-by-step explanation:
given xy/3
putting vales of x and y
(-2)(4)/3
-8/3