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coldgirl [10]
3 years ago
15

A client is a devout jew.what are two things that the nurse aide can do to make him comfortable?

Medicine
1 answer:
Ivanshal [37]3 years ago
4 0

Answer:

a, e

Explanation:

Ensure the facility food service knows he should get kosher meals.

ensure his medical procedures are not scheduled on the sabbath

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Which of the following is true regarding phase 3 of action potential?
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Answer:

calcium channel close.

Explanation:

In action potential there is phase 0, phase 1, phase 2, phase 3 and phase 4. In phase 3 of action potential there is a rapid repolarization phase in which calcium channels remain closed but potassium channels remain open and continuous outward movement or leakage of positive ions causes the outside environment positive and membrane potential goes to negative charge that is -85mV to -90mV

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Write stories books from Matilda and Charlie and the chocolate factory in short review what you like in them what you don't like
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What are the self-awareness skills has she developed? Why are they important?
ss7ja [257]
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What are the differences between otitis externa and otitis media??
Mashcka [7]

Answer:

<u>D & E</u>

Explanation:

Otitis media is inflammation in the middle ear.  Otitis externa is inflammation in the outer ear- external like “externa” is usually referenced as something “outside”.

5 0
2 years ago
A male carries a recessive mutation on the X chromosome that causes hemophilia, a blood clotting disorder. He marries a female w
artcher [175]

Answer:

Explanation:

Hemophilia is a X linked recessive genetic disorder caused by low amount of clotting factors. Hence, it becomes difficult to stop bleeding in case of an an injury and takes more time to clot. Here,

c= recessive allele for hemophilia gene

C= dominant allele for hemophilia gene

Genotype of male: XcY since he carries the recessive allele for hemophilia trait

Genotype of female: XCXc. She does not have hemophilia but her father had hemophilia so she she must have received one X chromosome from him and hence is a carrier for hemophilia.

Their children:

XcY  X   XCXc = XCXc,  XcXc,  XCY,  XcY

Out of resultant genotypes 2 out of 4 i.e. XcXc and XcY show hemophilia trait hence there is 50% probability that the child will have hemophilia.

6 0
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