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3 years ago

Mr. Caldwell divides 72 students into 12 groups. Solve the equation 72/s =12 find the number of students in each group.

Mathematics

2 answers:

RideAnS [48]3 years ago

3 0

Answer:

Step-by-step explanation:

72 divided by grops of 12 so 72/12 =6

jeka943 years ago

3 0

if you are trying to find out what is s it is 864 if not then no i multipled 12 and 72 and got 864 and then i divieded it and it was right . Again sorry if this is not what you were looking for

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How would I change this to standard form. <br><img src="https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20x%20-%201"

Pie

Answer:

x - 2y = 2

Step-by-step explanation:

the equation of a line in standard form is

Ax + By = C ( A is a positive integer and A, B are integers )

given y = $\frac{1}{2}$ x - 1

multiply through by 2 to eliminate the fraction

2y = x - 2 ( subtract 2y from both sides )

0 = x - 2y - 2 ( add 2 to both sides )

x - 2y = 2 ← in standard form

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3 years ago

Keith wants to save money to purchase a car. He buys an annuity with quarterly payments that earn 2.8% interest, compounded quar

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can you help me I'm doing a exam that ends in 7 min

Who must vote in favor of a bill that proposes statehood for a territory?

A. House of Representatives only

B. Senate only

C. House of Representatives and Senate

D. President of the United States

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2 years ago

Which of the following are solutions to the equation below?

sladkih [1.3K]

Answer:

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=3,\:x=-\frac{1}{2}$

Step-by-step explanation:

considering the equation

$2x^2\:-\:4x\:-\:3\:=\:x$

solving

$2x^2\:-\:4x\:-\:3\:=\:x$

$2x^2-4x-3-x=x-x$

$2x^2-5x-3=0$

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=2,\:b=-5,\:c=-3:\quad x_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

solving

$x=\frac{-\left(-5\right)+\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

$x=\frac{5+\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}$

$x=\frac{5+\sqrt{49}}{2\cdot \:2}$

$x=\frac{5+7}{4}$

$x=3$

also solving

$x=\frac{-\left(-5\right)-\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

$x=\frac{5-\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}$

$x=\frac{5-\sqrt{49}}{4}$

$x=-\frac{2}{4}$

$x=-\frac{1}{2}$

Therefore,

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=3,\:x=-\frac{1}{2}$

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3 years ago

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o-na [289]

Answer:

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Cloud [144]

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3 years ago

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