Question

Find the vertices of the hyperbola. Enter the smallest coordinate first.

Answer 1

Answer:

([-3], [0]), ([3], [0])

Step-by-step explanation:

The given equation of the hyperbola is presented as follows;

$\dfrac{x^2}{9} - \dfrac{y^2}{49} = 1$

The vertices of an hyperbola (of the form)  $\dfrac{x^2}{a^2} - \dfrac{y^2}{b^2} = 1$ are (± a, 0)

The given hyperbola can we presented in a similar form as follows;

$\dfrac{x^2}{9} - \dfrac{y^2}{49} = \dfrac{x^2}{3^2} - \dfrac{y^2}{7^2} = 1$

Therefore, by comparison, the vertices of the parabola are (± 3, 0), which gives;

The vertices of the parabola are ([-3], [0]), ([3], [0]).