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Sedaia [141]
3 years ago
12

Leila says that 75% of a number will always be greater than 50% of any other number. Complete one inequality to support Leilas c

laim and one to show that she is incorrect
Mathematics
2 answers:
Sholpan [36]3 years ago
7 0

Support

75% of 50 >  50%  of 2

Refute

75% of 2< 50% of 22

Greeley [361]3 years ago
6 0
If a number is positive, Leila's theory that 75% of a number will always be greater than 50% of another number is <em>true</em>;<em> </em>however, if both numbers are negative, or if the number of which she finds 50% is much greater than the number of which she finds 75%, Leila's theory could be incorrect.

This inequality shows that Leila is correct: 100(0.75) \geq 50(0.50) (which simplifies to 75 \geq 25)

This inequality shows that Leila is incorrect: 50(0.75) \geq 100(0.50) (which simplifies to 37.5 \geq 50)

Hope this helps!
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POSSIBLE
Levart [38]
I believe the answer is supplementary
7 0
3 years ago
Find a value for y for which the expression (1-y)(3-y)(6-y) has each given value
erik [133]

\\ \tt\Rrightarrow (1-y)(3-y)(6-y)=-70

\\ \tt\Rrightarrow -y(1+1)(3+1)(6+1)=-70

\\ \tt\Rrightarrow y(2)(4)(7)=70

\\ \tt\Rrightarrow y(56)=70

\\ \tt\Rrightarrow y=\dfrac{70}{56}

\\ \tt\Rrightarrow y=\dfrac{5}{4}

#2

\\ \tt\Rrightarrow (1-y)(3-y)(6-y)=120

\\ \tt\Rrightarrow -y(1+1)(3+1)(6+1)=120

\\ \tt\Rrightarrow -y(2)(4)(7)=120

\\ \tt\Rrightarrow 56y=-120

\\ \tt\Rrightarrow y=\dfrac{-120}{56}

\\ \tt\Rrightarrow y=\dfrac{-15}{7}

7 0
2 years ago
Read 2 more answers
Pls i really need help asap plsss help plsss plsss plsss help me i really need help and don't just put random answers put real a
Schach [20]

Answer:

The simple solutions are:

Right 6:  (-2+6,-3) = (4,3)

Left 6:    (-2-6,-3) = (-8,-3)

Up 6:      (-2,-3+6) = (-2, 3)

Down 6:  (-2,-3-6) = (-2,-9)

 

Those are for horizontal or vertical

line segments.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Solve this equation for x. (x+4) (x-2)=0
-BARSIC- [3]
1. -4
2. 2
four plus negative four is zero and two minus two is zero
7 0
3 years ago
F(x) = 5x^3+ 2x^2 - 90x - 36. <br><br> finding all zeros by factoring and explaining the steps
ella [17]

Answer:

f(x)=5x^3-2x^2-90x-36=0

=x^2(5x-2)-18(5x-2)=(x^2-18)(5x-2)=0

x^2-18=0/5x-2=0

x^2=18=x=9√2

5x-2=0

x=2/5

zeros are 9√2,2/5

8 0
3 years ago
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