:( pls helppp its due in 14 minutess

Mathematics

2 answers:

AleksAgata [21]3 years ago

6 0

Answer:

$2\frac{1}{8}$ inches

Step-by-step explanation:

$\frac{2}{8} + 1\frac{7}{8}$

notka56 [123]3 years ago

4 0

Answer:

Step-by-step explanation:

because 2/8 + 1 7/8 is 2 1/8

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If p(x) = 2x-4 and q(x)= x -3 what is (p o q)(x)

Fittoniya [83]

You replace the x in p(x) by x - 3:-

(p o q)(x) = 2(x - 3) - 4

= 2x - 10 (answer)

6 0

4 years ago

Calculate the l4 approximation for f(x) = cos2(x) on 8 , 2 . (round your answer to four decimal places.) l4 =

BaLLatris [955]

The solution for l4 is mathematically given as

L_{4}=0.5431

<h3>What is the solution for l4?</h3>

$&\text { Given } f(x)=a \cos ^{2}(x) \quad\left[\frac{\pi}{8}, \frac{\pi}{2}\right] \text { \& } n=4\\\\&\Delta a=\frac{b-a}{n}=\frac{\pi / 2-\pi / 8}{9}=\frac{3 \pi}{32}\\\\&x_{0}=\pi / 8, x_{1}=\frac{\pi}{8}+\frac{3 \pi}{32}=\frac{7 \pi}{32}\\\\&x_{2}=\frac{5 \pi}{16}, \quad x_{3}=\frac{13 \pi}{32}, x_{4}=\pi / 2\\\\&f\left(x_{0}\right)=f(1 / 8)=0.8535\\$

$&f\left(x_{1}\right)=f\left(\frac{7 \pi}{32}\right)=0.5975\\\\\&f\left(x_{2}\right)=f\left(\frac{5 \pi}{16}\right)=0.3086\\\\\&f\left(a_{3}\right)=f\left(\frac{13 \pi}{32}\right)=0.0842\\\\\&L_{4}=\sum_{k_{0}^{=0}}^{3} f\left(x_{k}\right) \Delta x\\\\&=\Delta \\\\x\left[f\left(x_{0}\right)+f\left(x_{1}\right)+f\left(x_{2}\right)+f\left(x_{3}\right)\right]\\\\\&=\frac{3 \pi}{32}[0.8535+0.5975+0.3056+0.0842]\\\\&L_{4}=0.5431$

Read more about approximation

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The complete Question is attached below

3 0

2 years ago

What is the solution to this equation? x/-4=8 A. x = -32 B. x = 2 C. x = 32 D. x = -2

ozzi

Hey! What you can do is plug them in or solve for x.
This is how you solve for x:
since its x is divided by -4 and you want to get x alone you should multiply -4 to the other side and so it would be x = -4*8.
That is -32.
The answer is A!
Hope this helps!

4 0

3 years ago

Read 2 more answers

Pls help!!!!! Thx and fast sry for rushing!!

Oxana [17]

the answer is 399 just go to socratic if you need help with math.