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Irina18 [472]
3 years ago
14

What quadrilaterals can you draw that have two sides with length 3 cm and two sides with length 7 cm​?

Mathematics
1 answer:
umka2103 [35]3 years ago
6 0

Answer:

Below.

Step-by-step explanation:

With these measures you can draw:

A rectangle.

A parallelogram.

A kite .

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Please help me !! im stuck with this !
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There  are 4 As and 3 Bs, so the ratio of Bs to the total number of As and Bs is ...

... (count of Bs) : (count of As + count of Bs)

... = 3 : (4 + 3)

... = 3 : 7

Expressed as a fraction, this is

... 3/7

6 0
3 years ago
Plz Help
weqwewe [10]
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when x=0,y=2; A(0,2)
when x=1,y=3; B(1,3)
**y=-x+8
when x=0,y=8; C(0,8)
when x=5,y=-3; D(5,-3)

The solution from the graph is S(2,4).

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3 years ago
Show that each statement is true: <br> Cos^4X-sin^4X=2cos^2X-1
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3 years ago
Evaluate. Express your answer in scientific notation.<br> 5.09 x 104 – 4.95 x 104
zvonat [6]

Answer:

-163.64..................

5 0
2 years ago
A survey asks, "If the husband in a family wants children, but the wife decides that she does not want any children, is it all r
vodka [1.7K]

Answer:

a. The 99% confidence interval for the population proportion is (0.7872, 0.8610).

D. Yes, we can conclude that the population proportion exceeds 75% because 75% is below the lowest believable value of the confidence interval.

b. The 99% confidence interval would be wider than a 95% confidence interval.

As the confidence level increases, the width interval increases, as we are requiring more confidence with the same information (there is no new sample). This means that, to be more confident, the only way is to include more values in the interval.

Step-by-step explanation:

We have to calculate a 99% confidence interval for the proportion.

The sample proportion is p=0.8241.

p=X/n=581/705=0.8241

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.8241*0.1759}{705}}\\\\\\ \sigma_p=\sqrt{0.000206}=0.0143

The critical z-value for a 99% confidence interval is z=2.5758.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_p=2.5758 \cdot 0.0143=0.0369

Then, the lower and upper bounds of the confidence interval are:

LL=p-z \cdot \sigma_p = 0.8241-0.0369=0.7872\\\\UL=p+z \cdot \sigma_p = 0.8241+0.0369=0.8610

The 99% confidence interval for the population proportion is (0.7872, 0.8610).

We can conclude that there is, at least, 99% chances that the true proportion is higher than 0.7872. So there is at least 99% chances that the population proportion is higher than 0.75.

4 0
3 years ago
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