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Paladinen [302]
3 years ago
15

Evaluate the expression when x=8 and y=2. 3x-5y 5(x y)

Mathematics
1 answer:
lubasha [3.4K]3 years ago
3 0
I hope this helps you

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What is the Lcm of 2 and 7
wel

Answer:

14

Step-by-step explanation:

The least common multiple is a number that both numbers can multiply something to get to, and the smallest possible common one.

Let's try listing out the multiples of 2:

2, 4, 6, 8, 10, 12, 14, 16, 18, 20

And the multiples of 7:

7, 14, 21, 28, 35, 42, 49, 56, 63, 70

Notice that both have the number 14 in common, and it is the first number that they do so.  There are lots of other multiples that they have in common too, but 14 is the least.

5 0
2 years ago
G(x)= 3x − 3; Find g(−6)
Irina18 [472]
<span>g(x)= 3x − 3
</span><span>g(−6)

g(-6) = 3(-6) - 3
g(-6) = -18 - 3
g(-6) = -21

The answer is -21.</span>
4 0
3 years ago
Read 2 more answers
Find the value of the variable
Neporo4naja [7]

Answer:

x=6

Step-by-step explanation:

I would look at this triangle and notice that x can be solved by setting up a ratio.

I generally put the short side of the triangle on the top and the long side on the bottom

4/x = x/9

You then cross multiply to get 36=x^2, or +-6=x

A length of a triangle cannot be negative, so we are left with the answer x=6

8 0
3 years ago
What is the equation of a circle whose center is (2,0) and has a radius= 9?
Flauer [41]
The equation of a circle is: (x - h)² + (y - k)² = radius² where (h, k) is the center. Now just plug in your given information and simplify.

(x - 2)² + (y - 0)² = 9²

Your equation is:
(x - 2)² + y² = 81
6 0
3 years ago
Read 2 more answers
4a/3-b/4=6<br> 5a/6+b=13<br> Solve linear system by elimination
kondor19780726 [428]
\bf \cfrac{4a}{3}-\cfrac{b}{4}=6&#10;\qquad \qquad &#10;\cfrac{5a}{6}+b=13&#10;\\\\\\&#10;\textit{let us remove the denominators off those folks}\\&#10;\textit{by multiplying the first one by 12, both sides}\\&#10;\textit{and the second one by 6, both sides, thus}&#10;\\\\\\&#10;12\left( \cfrac{4a}{3}-\cfrac{b}{4} \right)=12(6)\implies 16a-4b=72&#10;\\\\\\&#10;6\left( \cfrac{5a}{6}+b \right)=6(13)\implies 5a+6b=78

\bf  \textit{now, let's do the elimination}&#10;\\\\&#10;&#10;\begin{array}{llll}&#10;16a-4b=72&\boxed{\times 3}\implies &48a-\underline{12b}=216\\\\&#10;5a+6b=78&\boxed{\times 2}\implies &10a+\underline{12b}=156\\&#10;&&--------\\&#10;&&58a+0\quad=372&#10;\end{array}

solve for "a", once you get "a", plug it back into either equation to get "b"
3 0
2 years ago
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