3 years ago

Please Helppp!!! Will give brainly if correct! 50 points

Mathematics

2 answers:

gulaghasi [49]3 years ago

8 0

The answer to this question is C. Multiply A by 3 and B by 2

ki77a [65]3 years ago

4 0

C, multiply A by 3 and B by 2.

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Calculate the length.

Nataly_w [17]

A^2 + B^2 = C^2

6^2 + B^2 = 7^2

36 + B^2 = 49

B^2 = 13

B = 3.61

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5 0

3 years ago

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I need help with these as well

Mkey [24]

The answer to c. Is 8t+12g

4 0

3 years ago

The ratio of berries to Oranges is 10:1 if there are 25 oranges how many berries would there be

Yuki888 [10]

Answer:

250 berries

Step-by-step explanation:

10 to 1 means 10 times as many berries as oranges

25x10=250

8 0

3 years ago

Find the solution of the initial value problem<br><br> dy/dx=(-2x+y)^2-7 ,y(0)=0

Leokris [45]

Substitute $v(x)=-2x+y(x)$ , so that $\dfrac{\mathrm dv}{\mathrm dx}=-2+\dfrac{\mathrm dy}{\mathrm dx}$ . Then the ODE is equivalent to

$\dfrac{\mathrm dv}{\mathrm dx}+2=v^2-7$

which is separable as

$\dfrac{\mathrm dv}{v^2-9}=\mathrm dx$

Split the left side into partial fractions,

$\dfrac1{v^2-9}=\dfrac16\left(\dfrac1{v-3}-\dfrac1{v+3}\right)$

so that integrating both sides is trivial and we get

$\dfrac{\ln|v-3|-\ln|v+3|}6=x+C$

$\ln\left|\dfrac{v-3}{v+3}\right|=6x+C$

$\dfrac{v-3}{v+3}=Ce^{6x}$

$\dfrac{v+3-6}{v+3}=1-\dfrac6{v+3}=Ce^{6x}$

$\dfrac6{v+3}=1-Ce^{6x}$

$v=\dfrac6{1-Ce^{6x}}-3$

$-2x+y=\dfrac6{1-Ce^{6x}}-3$

$y=2x+\dfrac6{1-Ce^{6x}}-3$

Given the initial condition $y(0)=0$ , we find

$0=\dfrac6{1-C}-3\implies C=-1$

so that the ODE has the particular solution,

$\boxed{y=2x+\dfrac6{1+e^{6x}}-3}$

5 0

3 years ago

A diver descends to a depth of –25.6 feet relative to sea level. How many feet must the diver ascend to reach sea level?

MArishka [77]

Answer:

the Answer would be c

Step-by-step explanation:

5 0

2 years ago

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