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mrs_skeptik [129]
2 years ago
8

How many 1/4 inch lengths of rod can be cut from 3 1/2 inch rod

Mathematics
1 answer:
stepan [7]2 years ago
5 0

Answer:

14

Step-by-step explanation:

Shown in picture above.

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Find the distance between (-2,6) and (1,2)
olga nikolaevna [1]

Step-by-step explanation:

label the numbers (x,y) and (x2,y2)

write down the distance formula

replace the xs and ys by the numbers and then solve them

3 0
3 years ago
Please help in really stuck ​
sattari [20]

\int\limits {\pi y^2} \, dy

y = 2 + x^6

y - 2 = x^6

x = (y - 2)^1/6

\pi \int\limits^3_2 {(y - 2)^{1/6}} \, dx

Well, solving this integral

\pi \int\limits^3_2 {(y - 2)^{1/6}} \, dx = 2,69279

6 0
3 years ago
PLEASE HELP ME ASAP!!!
MatroZZZ [7]

You start with 5 baseball cards and purchase 10 cards every week until you have at most 45 cards.

10 cards every week = 10 w

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3 0
2 years ago
Fill in the blank. ___ x 9 = 45? Please
tia_tia [17]

Answer:

The correct answer is "5"

5 times 9 equals 45.

5 x 9 = 45

6 0
2 years ago
Read 2 more answers
In isosceles $\triangle abc$ (with $ab = ac$), point $d$ lies on $ab$ such that $cd = cb$. if $\angle adc = 115^\circ$, what is
Nuetrik [128]

1. Angles ADC and CDB are supplementary, thus

m∠ADC+m∠CDB=180°.

Since m∠ADC=115°, you have that m∠CDB=180°-115°=65°.

2. Triangle BCD is isosceles triangle, because it has two congruent sides CB and CD. The base of this triangle is segment BD. Angles that are adjacent to the base of isosceles triangle are congruent, then

m∠CDB=m∠CBD=65°.

The sum of the measures of interior angles of triangle is 180°, therefore,

m∠CDB+m∠CBD+m∠BCD=180° and

m∠BCD=180°-65°-65°=50°.

3. Triangle ABC is isosceles, with base BC. Then

m∠ABC=m∠ACB.

From the previous you have that m∠ABC=65° (angle ABC is exactly angle CBD). So

m∠ACB=65°.

4. Angles BCD and DCA together form angle ACB. This gives you

m∠ACB=m∠ACD+m∠BCD,

m∠ACD=65°-50°=15°.

Answer: 15°.

3 0
3 years ago
Read 2 more answers
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