The problem express that the fraction of time
worked by the three people need to be equivalent to one person working full
time. This means that the fraction need to add up to one. We know one person
works ½ time on the project and another works one third 1/3 time.
Given:
A = the amount of time that the third person needs
to work on the job to add up to one
1 = ½ +1/3 + A
1 – ½ - 1/3 = A
To subtract the fractions put them all over a
common denominator. Use 3 * 2 as the denominator.
1=6/6, ½ = 3/6, 1/3 = 2/6
A = 6/6 – 3/6 – 2/6
<span>A = 1/6 , The third person must work on the project</span>
Answer:
590 would be your answer
Step-by-step explanation:
Step-by-step explanation:
solution:- from LHS 1-cos²x/sinx
∵ 1-cos²x = sin²x
∴ sin²x /sinx = sinx
from RHS tanx × cosx
∵tanx = sinx×cosx
∴ sinx/ cosx × cosx = sinx
Since, LHS = RHS proved ___
Answer:
Yes.
Step-by-step explanation:
You can find it out by factoring but ill do it easier way.
(x + 1 ) = 0 put the first and second equation to 0
x = -1
x³ + 2x² - 5x - 6 = 0 Now plug in the x in the equation
(-1)³ + 2(-1)² - 5(-1) - 6 = 0
0 = 0
so (x + 1) is a factor.
