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3 years ago

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The cargo box of an 18-wheeler truck has an inside length of 39.6 feet,width of 7.6 feet,and a height of 8.8 feet.What is the ca

rrying capacity (volume) of the cargo box of this truck?Explain your thinking.

1 answer:

kipiarov [429]3 years ago

3 0

Sorry this is not related to your question but can you checkout my questions on my account/profile because I need help!!! (:

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If c is the curve given by \mathbf{r} \left( t \right = \left( 1 5 \sin t \right \mathbf{i} \left( 1 3 \sin^{2} t \right \mathbf

jonny [76]

With the curve $C$ parameterized by

$C:\mathbf r(t)=\underbrace{15\sin t}_{x(t)}\,\mathbf i+\underbrace{13\sin^2t}_{y(t)}\,\mathbf j+\underbrace{12\sin^3t}_{z(t)}\,\mathbf k$

with $0\le t\le\dfrac\pi2$ , and given the vector field

$\mathbf f(x,y,z)=x\,\mathbf i+y\,\mathbf j+z\,\mathbf k$

the work done by $\mathbf f$ on a particle moving on along $C$ is given by the line integral

$\displaystyle\int_C\mathbf f\cdot\mathrm d\mathbf r=\int\limits_{t=0}^{t=\pi/2}\mathbf f(x(t),y(t),z(t))\cdot\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\,\mathrm dt$

where

$\mathrm d\mathbf r=(15\cos t\,\mathbf i+26\sin t\cos t\,\mathbf j+36\sin^2t\cos t\,\mathbf k)\,\mathrm dt$

The integral is then

$\displaystyle\int_0^{\pi/2}(15\sin t\,\mathbf i+13\sin^2t\,\mathbf j+12\sin^3t\,\mathbf k)\cdot(15\cos t\,\mathbf i+13\sin2t\,\mathbf j+18\sin t\sin2t\,\mathbf k)\,\mathrm dt$
$=\displaystyle\int_0^{\pi/2}(432\sin^5t\cos t+338\sin^3t\cos t+225\sin t\cos t$
$=269$

6 0

3 years ago

1/2 of 3oz, 3/4 of 3oz and 1/3 of 2oz, how many ounces of food was consumed

Alex Ar [27]

4.42 ounces of food was consumed. 1/2 of 3 oz equals 1.5 oz, 3/4 of 3 oz equals 2.25 oz and 1/3 of 2 oz equals .67 and when you add those up you get 4.42.

3 0

3 years ago

Interpret the following table about school dropout at the basic level (5 marks)

barxatty [35]

Answer:

Step-by-step explanation:

Given the following :

- - - Jhs

Basic level - - - - Boys - - - - Girls - - - - Total

Primary - - - - - - - 49 - - - - - - 51 - - - - - - 100%

Jhs - - - - - - - - - - 56 - - - - - - 44. - - - - - - 100%

With the information above,

Primary Dropout percentage:

BOYS : [49 / (49 +51)] × 100.= 49%

GIRLS : [51 / (49 +51)] × 100.= 51%

Jhs: Dropout percentage

BOYS : [56 / ( 56 + 44) × 100 = 56%

GIRLS : [44 / (44 +56)] × 100.= 44%

8 0

3 years ago

Solve for X<br><br> PLEASE HELP ME

guapka [62]

Answer:

x = 10°

Step-by-step explanation:

Step 1:

92° + x° + 78° = 180° Supplementary Angles

Step 2:

x° + 170° = 180° Combine Like Terms

Step 3:

x° = 180° - 170° Subtract 170° on both sides

Answer:

x = 10°

Hope This Helps :)

4 0

3 years ago

Complete the Magic Square.

quester [9]

Answer:

+5

Step-by-step explanation:

So you can see the 5 pattern, so you add 9+5= 14 which goes in the middle square and 14+5=18 in the left square

Now between 18 and 11 it is 7 so you subtract 7 which equals 4 then - 5= -1 then -5= -6

5 0

3 years ago

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