Two consecutive odd integers have a difference of 2. If you let the smaller one of them be x, the other one is x + 2.
Their sum is -36, so add x and x + 2, and set equal to -36. Then solve for x to find the smaller one. Finally, 2 more than x is the greater of the two integers.
x + x + 2 = -36
2x + 2 = -36
2x = -38
x = -19
The smaller one of the two integers is -19.
x + 2 = -19 + 2 = -17
The greater of the two integers is -17.
Answer: The integers are -19 and -17.
I think it’s 60 if that’s what your asking
Answer:
3x-1
Step-by-step explanation:
6 +(-x) +2x + (-7) + 2x=
6-x +2x -7 + 2x =
6-7+ 2x+2x-x=
-1 + 3x=
3x-1
The total weight of candies is unknown. Let x = the total weight of candies.
"One student ate 3/20 of all candies and another 1.2 lb":
The first student ate (3/20)x plus 1.2 lb which is 0.15x + 1.2.
"The second student ate 3/5 of the candies and the remaining 0.3 lb."
The second student ate (3/5)x and 0.3 lb which is 0.6x + 0.3.
Altogether the 2 students ate 0.15x + 1.2 + 0.6x + 0.3.
That was all the amount of candies, so that sum equals x.
0.15x + 1.2 + 0.6x + 0.3 = x
Now we solve the equation for x to find what the total amount of candies was.
0.75x + 1.5 = x
-0.25x = -1.5
x = 6
The total amount of candies was 6 lb.
The first student ate 0.15x + 1.2 = 0.15(6) + 1.2 = 0.9 + 1.2 = 2.1, or 2.1 lb of candies.
The second student ate 0.6x + 0.3 = 0.6(6) + 0.3 = 3.6 + 0.3 = 3.9, or 3.9 lb of candies.
Answer: The first student ate 2.1 lb of candies, and the second student ate 3.9 lb of candies.
