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Neporo4naja [7]

3 years ago

12

Are these questions different at all? And if so whats the answer to them?

1 answer:

konstantin123 [22]3 years ago

3 0

Answer:

i think u got it

Step-by-step explanation:

You might be interested in

Condense the following logs into a single log:

mamaluj [8]

QUESTION 1

The given logarithm is

$8\log_g(x)+5\log_g(y)$

We apply the power rule of logarithms; $n\log_a(m)=\log_(m^n)$

$=\log_g(x^8)+\log_g(y^5)$

We now apply the product rule of logarithm;

$\log_a(m)+\log_a(n)=\log_a(mn)$

$=\log_g(x^8y^5)$

QUESTION 2

The given logarithm is

$8\log_5(x)+\frac{3}{4}\log_5(y)-5\log_5(z)$

We apply the power rule of logarithm to get;

$=\log_5(x^8)+\log_5(y^{\frac{3}{4}})-\log_5(z^5)$

We apply the product to obtain;

$=\log_5(x^8\times y^{\frac{3}{4}})-\log_5(z^5)$

We apply the quotient rule; $\log_a(m)-\log_a(n)=\log_a(\frac{m}{n} )$

$=\log_5(\frac{x^8\times y^{\frac{3}{4}}}{z^5})$

$=\log_5(\frac{x^8 \sqrt[4]{y^3} }{z^5})$

7 0

3 years ago

Write three numbers that are greater than 543,00 but less than 544,00

sveticcg [70]

54330, 54360, 54399 are all numbers that are lower than 54400 but greater than 54300

5 0

3 years ago

MARK AS BRIANLEST IF ANSWER RIGHT

marishachu [46]

Answer:

x= 13

Step-by-step explanation:

−4/9(18x − 36) = −88

we need to solve the equation for x

$\frac{-4}{9}(18x - 36) = -88$

First we remove the fraction -4/9

Multiply by -9/4 on both sides

$\frac{-9}{4}*\frac{-4}{9}(18x - 36) = -88*\frac{-9}{4}$

18x -36 = 198

Now add 36 on both sides

18x = 234

Divide both sides by 18

x = 13

8 0

3 years ago

The distribution of passenger vehicle speeds traveling on a certain freeway in California is nearly normal with a mean of 71.5 m

Zinaida [17]

Answer:

a

$G = 0.007523$

b

The number of cars the highway patrol officer would watch before a car that is seen is $E(X) = 1.6027$

The standard deviation is $s = 0.9829$

gg

Step-by-step explanation:

From the question we are told that

The mean is $\mu = 71.5 \ miles/hour$

The standard deviation is $\sigma = 4.75 \ miles/hour$

The speed limit is $x = 70 \ miles /hour$

Generally the probability of getting a car that is moving with speed greater than the speed limit is mathematically represented as

$p =P(X > x ) = P(X > 70) = P(\frac{X - \mu }{\sigma } > \frac{70 - 71.5 }{4.75})$

=> $p= P(X > 70) = P(\frac{X - \mu }{\sigma } > \frac{70 - 71.5 }{4.75})$

=> $p= P(X > 70) = P(\frac{X - \mu }{\sigma } > -0.31579 )$

Here

$\frac{X - \mu }{\sigma } = Z(The \ standardized \ value \ of X )$

So

=> $p= P(X > 70) = P(Z > -0.31579 )$

From the z-table

$p = P(Z > -0.31579 ) = 0.62392$

So

$p = P(X > 70) = 0.62392$

Generally the probability of getting a car that is not moving with speed greater than the speed limit is mathematically represented as

$q = 1 - p$

=> $q = 1 - 0.62392$

=> $q = 0.37608$

Generally the probability of getting 5 cars that are not speeding is mathematically represented as

$G = q^5$

=> $G = (0.37608)^5$

=> $G = 0.007523$

Generally the number of cars that the highway patrol officer is expected to watch until the first car that is speeding is gotten is mathematically represented as

$E(X) = \frac{1}{p}$

=> $E(X) = \frac{1}{0.62392}$

=> $E(X) = 1.6027$

Generally the standard deviation is mathematically represented as

$s = \sqrt{\frac{1 - p }{ p^2} }$

=> $s = \sqrt{\frac{1 -0.62392 }{ (0.62392)^2} }$

=> $s = 0.9829$

8 0

3 years ago

A jar contains 20 coins.

faltersainse [42]

Answer:

2p 30

Step-by-step explanation:

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8 0

4 years ago