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damaskus [11]
3 years ago
12

What is the graph of the equation 9x^2 + 4y^2 - 18x + 8y - 23 = 0 ? Also, how did you get that?

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
8 0
13xy^2-10xy-23=0

you first add the like terms and rewrite and thats how you get the answer
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Step-by-step explanation:

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Step-by-step explanation:

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In this lesson, you learned new formulas to find the area of a triangle. How are these formulas different from the commonly know
Yuki888 [10]
Aside from the conventional formula for triangle, A=<span>½bh which is only applicable to problems where the base and height are already given and the triangle is a right triangle having a degree of 90. There are some formulas in getting the area of a triangle:

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3 0
3 years ago
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
ddd [48]

Answer:

f'(x) = 4x^2 - 3 for x \le -3

Step-by-step explanation:

See attachment for proper question

Given

f(x) = -\frac{1}{2}\sqrt{x + 3}

For

x \ge -3

Required

Determine the inverse function

f(x) = -\frac{1}{2}\sqrt{x + 3}

Replace f(x) with y

y = -\frac{1}{2}\sqrt{x + 3}

Swap the positions of x and y

x = -\frac{1}{2}\sqrt{y + 3}

Multiply both sides by -2

-2 * x =-2 *  -\frac{1}{2}\sqrt{y + 3}

-2x =\sqrt{y + 3}

Square both sides

(-2x)^2 =(\sqrt{y + 3})^2

4x^2 =y + 3

Make y the subject

y = 4x^2 - 3

The inverse has been solved. So, we need to replace y with f'(x)

f'(x) = 4x^2 - 3

Next, is to determine the interval

x \ge -3

Change inequality to \le

x \le -3

Hence, the inverse function is:

f'(x) = 4x^2 - 3 for x \le -3

7 0
3 years ago
Tell whether each graph is a function and justify your answer. Which graph is not a good representation of a​ real-world situati
mina [271]

Using the function concept, it is found that:

  • Graph B is a function because each value of x corresponds to exactly one y-value.

In a function, <u>one value of the input can be related to only one value of the output</u>.

  • In a graph, it means that for each value of x(horizontal axis), there can be only one respective value of y(vertical axis).

In this problem, at Graph A, when x = 5, for example a vertical line crosses the function 3 times, hence there are 3 respective values of y for x = 5, and the same is valid for other values of x, hence it is not a function.

At Graph B, <u>for each value of x, there is only one value of y</u>, hence it is a function.

Hence:

Graph B is a function because each value of x corresponds to exactly one y-value.

To learn more about the function concept, you can take a look at brainly.com/question/12463448

5 0
2 years ago
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