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NikAS [45]
2 years ago
11

Solve for a and x in ax^2=48​

Mathematics
1 answer:
Gelneren [198K]2 years ago
6 0

Answer:

ax^2 = 48\\a = \frac{48}{x^2}

ax^2 = 48\\x^2 = \frac{48}{a} \\x = \frac{\sqrt{48} }{\sqrt{a} } \\x = \frac{4\sqrt{3} }{\sqrt{a}}  \\x = \frac{4\sqrt{3a} }{a}

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What is the constant rate of change shown in the graph?
AnnyKZ [126]

Answer:

10

Step-by-step explanation:

For every lawn mowed, the amount earned increases by 10 dollars

8 0
3 years ago
A triangular lot has sides of 215m, 185m, and 125m. Find the measures of the angles at its corners
Vlada [557]

Answer:

The measures of the angles at its corners are 59.1\°,35.4\°,85.5\°

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the measure of angle A

Applying the law of cosines

185^{2}= 215^{2}+125^{2}-2(215)(125)cos(A)

2(215)(125)cos(A)= 215^{2}+125^{2}-185^{2}

cos(A)= [215^{2}+125^{2}-185^{2}]/(2(215)(125))cos(A)=0.513953

A=arccos(0.513953)=59.1\°

step 2

Find the measure of angle B

Applying the law of cosines

125^{2}= 215^{2}+185^{2}-2(215)(185)cos(B)

2(215)(185)cos(B)= 215^{2}+185^{2}-125^{2}

cos(B)= [215^{2}+185^{2}-125^{2}]/(2(215)(185))cos(B)=0.81489

B=arccos(0.81489)=35.4\°

step 3

Find the measure of angle C

Applying the law of cosines

215^{2}= 125^{2}+185^{2}-2(125)(185)cos(C)

2(125)(185)cos(C)= 125^{2}+185^{2}-215^{2}

cos(C)= [125^{2}+185^{2}-215^{2}]/(2(125)(185))cos(C)=0.0784

C=arccos(0.0784)=85.5\°

3 0
3 years ago
A triangle has an area of 160 square inches. If it has a height of 10 inches, what is its base length?
inn [45]

Answer:

The answer is:

32 inches

Step-by-step explanation:

The reason to why is because a triangle's area is always length times height divided by 2. In this case we need to reverse the steps and multiply 160 by 2 to get 320. Then divide the area of 320 by 10 to get 32 inches to be the base length.

Hope you have a wonderful day :)

6 0
3 years ago
Researchers are studying the distribution of subscribers to a certain streaming service in different populations. From a random
Katen [24]

Answer:

CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}

Step-by-step explanation:

Given

n = 200

x_1 = 34 -- City C

x_2 = 54 --- City K

Required

Determine the 90% confidence interval

This is calculated using:

CI = \bar x \± z\frac{\sigma}{\sqrt n}

Calculating \bar x

\bar x = \bar x_1 - \bar x_2

\bar x = \frac{x_1}{n} - \frac{x_2}{n}

\bar x = \frac{34}{200} - \frac{54}{200}

\bar x = 0.17 - 0.27

For a 90% confidence level, the ​z-score is 1.65.  So:

z = 1.65

Calculating the standard deviation \sigma

\sigma = \sqrt{(\bar x_1)*(1 - \bar x_1) + (\bar x_2)*(1 - \bar x_2) }

So:

\sigma = \sqrt{(0.17)*(1 - 0.17) + (0.27)*(1 - 0.27) }

\sigma = \sqrt{(0.17)*(0.83) + (0.27)*(0.73)}

So:

CI = (0.17 - 0.27)\± 1.65\frac{\sqrt{(0.17)*(0.83) + (0.27)*(0.73)}}{\sqrt {200}}

CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}

7 0
2 years ago
Can you help me ? please ??
natali 33 [55]
60 miles per hour
so 156 miles = 156 /60 = 2.6 hours 
0.6 x 60 = 36
so 2.6 hours  = 2 hours 36 minutes

Kim leaves Rotherham at 7: 30AM
7:30 AM + 2 hours 36 minutes = 10:06 AM

Answer
Kim arrives in London after 10AM





6 0
3 years ago
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