Answer:
titutex=cos\alp,\alp∈[0:;π]
\displaystyle Then\; |x+\sqrt{1-x^2}|=\sqrt{2}(2x^2-1)\Leftright |cos\alp +sin\alp |=\sqrt{2}(2cos^2\alp -1)Then∣x+
1−x
2
∣=
2
(2x
2
−1)\Leftright∣cos\alp+sin\alp∣=
2
(2cos
2
\alp−1)
\displaystyle |\N {\sqrt{2}}cos(\alp-\frac{\pi}{4})|=\N {\sqrt{2}}cos(2\alp )\Right \alp\in[0\: ;\: \frac{\pi}{4}]\cup [\frac{3\pi}{4}\: ;\: \pi]∣N
2
cos(\alp−
4
π
)∣=N
2
cos(2\alp)\Right\alp∈[0;
4
π
]∪[
4
3π
;π]
1) \displaystyle \alp \in [0\: ;\: \frac{\pi}{4}]\alp∈[0;
4
π
]
\displaystyle cos(\alp -\frac{\pi}{4})=cos(2\alp )\dotscos(\alp−
4
π
)=cos(2\alp)…
2. \displaystyle \alp\in [\frac{3\pi}{4}\: ;\: \pi]\alp∈[
4
3π
;π]
\displaystyle -cos(\alp -\frac{\pi}{4})=cos(2\alp )\dots−cos(\alp−
4
π
)=cos(2\alp)…
1
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If the value of θ is 46.4°. Then the value of the cosine of θ will be 20/29.
<h3>What is trigonometry?</h3>
The connection between the lengths and angles of a triangular shape is the subject of trigonometry.
The value of sine of θ is 21/29.
Then the value of θ will be
sin θ = 21/29
θ = sin⁻¹(21 / 29)
θ = 46.4°
Then the value of the cosine of θ will be
cos θ = cos 46.4°
cos θ = 20/29
More about the trigonometry link is given below.
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Answer:
it is the 2nd choice
Step-by-step explanation:
i got Aced my test
Writing the problem as an equation you have:
2x+6 > -16
Solve for x:
2x+6 > -16
Subtract 6 from each side:
2x > -22
Divide both sides by 2:
x > -11
The answer is: x > -11
Answer:
Look at the desmos graph below
Step-by-step explanation: