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Hatshy [7]
2 years ago
13

Solve the following system of equations.

Mathematics
2 answers:
DIA [1.3K]2 years ago
7 0
2x+y-3=0,x-2y=1 okay that's the answer good luck
Elanso [62]2 years ago
5 0
Subtract y from both sides
now we have
2x = -y + 3
divide both sides by 3
x= -y/2 + 3/2
the other x equals 2y +1, set these equal to eachother

2y + 1 = -y/2 + 3/2

add y/2 to both sides

2.5y + 1 = 3/2

subtract 1 from both sides

2.5y = 0.5

divide both sides by 2.5

y=0.2

plug in 0.2 for y in an original equation

x = 2(0.2) + 1

solve

x = 1.4

ANSWER:
x= 1.4
y= 0.2
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3 years ago
Divide z4 by z-3<br><br>A. z1<br>B. z7<br>C. z-12<br>D. z12<br>E. z-7
lakkis [162]
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5 0
3 years ago
Write a formula for quadratic function if its graph has the vertex at point (0,6) and passes through the point (−1,−2).
d1i1m1o1n [39]

Answer:

y = - 8x² + 6

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (0, 6), thus

y = a(x - 0)² + 6, that is

y = ax² + 6

To find a substitute (- 1, - 2) into the equation

- 2 = a(- 1)² + 6, that is

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4 0
2 years ago
What is x-10=12 give me a example
ella [17]

Answer:

x = 22

Step-by-step explanation:

x-10=12

We want to solve for x

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3 0
3 years ago
Read 2 more answers
In the trapezoid ABCD ( AB ∥ CD ) point M∈ AD , so that AM:MD=3:5. Line l ∥ AB and going trough point M intersects diagonal AC a
geniusboy [140]

Answer:

BC:BN=8:3

Step-by-step explanation:

ABCD is a trapezoid and there is a point m which belongs to AD such that AM:MD=3:5.Line "l" parallel to AB intersects the diagonal AC at p and BD at N.

Now, we know that the parallel lines divide the transversal into the segments with equal ratio, therefore, BN:NC=AM:MD

But, BC= BN+NC

Therefore, BC:BN=(BN+NC):BN

⇒BC:BN=(3+5):3

⇒BC:BN=8:3


4 0
3 years ago
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