Question

Solve the following system of equations.

Answer 1

2x+y-3=0,x-2y=1 okay that's the answer good luck

Answer 2

Subtract y from both sides
now we have
2x = -y + 3
divide both sides by 3
x= -y/2 + 3/2
the other x equals 2y +1, set these equal to eachother

2y + 1 = -y/2 + 3/2

add y/2 to both sides

2.5y + 1 = 3/2

subtract 1 from both sides

2.5y = 0.5

divide both sides by 2.5

y=0.2

plug in 0.2 for y in an original equation

x = 2(0.2) + 1

solve

x = 1.4

ANSWER:
x= 1.4
y= 0.2