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Hatshy [7]
3 years ago
13

Solve the following system of equations.

Mathematics
2 answers:
DIA [1.3K]3 years ago
7 0
2x+y-3=0,x-2y=1 okay that's the answer good luck
Elanso [62]3 years ago
5 0
Subtract y from both sides
now we have
2x = -y + 3
divide both sides by 3
x= -y/2 + 3/2
the other x equals 2y +1, set these equal to eachother

2y + 1 = -y/2 + 3/2

add y/2 to both sides

2.5y + 1 = 3/2

subtract 1 from both sides

2.5y = 0.5

divide both sides by 2.5

y=0.2

plug in 0.2 for y in an original equation

x = 2(0.2) + 1

solve

x = 1.4

ANSWER:
x= 1.4
y= 0.2
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A hot air balloon rose from ground level to 1000 feet in order to pass over a mountain. The balloon then descended 800 feet to a
RSB [31]

Answer:

200ft.

Step-by-step explanation:

It's 200ft because you just do 1000 - 800 = 200ft

8 0
3 years ago
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Nvmmmm I got the answer lol
forsale [732]

Answer:

A. none

Step-by-step explanation:

7 0
2 years ago
The function, f(x) = –2x2 + x + 5, is in standard form. The quadratic equation is 0 = –2x2 + x + 5, where a = –2, b = 1, and c =
maw [93]

Answer:

To solve for the zeros of the function equate f(x) = 0

That's

- 2x² + x + 5 = 0

Using the quadratic formula

x =  \frac{ - b± \sqrt{ {b}^{2}  - 4ac} }{2a}

a = - 2 b = 1 c = 5

And from the question

b² - 4ac = 41

So we have

x =  \frac{ -  1±  \sqrt{41} }{2( - 2)}  =  \frac{ - 1± \sqrt{41} }{ - 4}

x =  \frac{1± \sqrt{41} }{4}

We have the final answer as

x =  \frac{1   + \sqrt{41} }{4}  \:  \:  \:  \: or \:  \:  \:  \: x =  \frac{1 -  \sqrt{41} }{4}

Hope this helps you

4 0
3 years ago
Read 2 more answers
Geraldine is asked to explain the limits on the range of an exponential equation using the function f(x) = 2^x. She makes these
GalinKa [24]

<u>General Idea:</u>

Domain is the values of x which gives a defined output to the function, and Range is the values of y that we get by substituting domain values of x. For the function f(x) = a^x, where a > 0, the domain will be all real numbers and range will be all values greater than 0. That is the graph will be very close to x-axis but will never touch it.

<u>Applying the concept:</u>

From the attached table, we can notice that as x increases infinitely, the y-values are continually doubled for each single increase in x and as x decreases infinitely, the y-values are continually halved for each single decrease in x.

Option 1: "Statement 1 is incorrect because the y-values are increased by 2, not doubled".

Option 1 is INCORRECT because Statement 1 is TRUE & CORRECT.

Option 2: "Statement 2 is incorrect because the y-values are doubled, not halved".

Option 2 is INCORRECT because Statement 2 is TRUE & CORRECT.

Option 3: "The conclusion is incorrect because the range is limited to the set of the integers"

Option 3 is INCORRECT because, the range will be always greater than 0, because irrespective of how many times y is halved for each single decrease in x, the y will still be a positive fraction and won't be a negative.

Option 4: "The conclusion is incorrect because the range is limited to the set of positive real numbers"

<em><u>Option 4 is CORRECT because y value will be positive irrespective of whatever x we substitute in the function.</u></em>

8 0
3 years ago
Read 2 more answers
9/10 + -4/5 help please
Maru [420]

Answer:

1/10

Step-by-step explanation:

First you've got to find common denominators. The common denominator would be 10 since 10 is divisible by 5 and 10. That means you've got the change the denominator of -4/5. Multiply both the numerator and denominator by 2 to grt -8/10.

Then all you have to do is:

9 + -8 1

——— = —

10 10

Khan academy also has some great videos on this if you're confused.

7 0
3 years ago
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