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Degger [83]
3 years ago
11

A line has the equation y=1/3x-5 . Find the equation of a perpendicular line passing through (3, 2).

Mathematics
1 answer:
stiks02 [169]3 years ago
6 0
Slope of the line is ⅓. Slope of perpendicular to line is -3.
Point-slope equation for line of slope -3 that passes through (3,2):
y-2 = -3(x-3)
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Write an equation in point-slope form of the line that passes through the point (−3,6) and has a slope of 5.
strojnjashka [21]

Answer:

Below in bold.

Step-by-step explanation:

Point slope form is y - y1 = m(x - x1)

where m = the slope of the line and (x1, y1) is a point on the line.

Here m = 5, x1 = -3 and y1 = 6.

So we have:

y - 6 = 5( x - (-3))

y - 6 = 5(x + 3)   (Answer)

3 0
2 years ago
Pls help asap...urgently help needed!!!<br>tia
ziro4ka [17]

Answer:

(a) v =  1536640/ m^2.

(b)  (i)   1186 m/s.

     (ii)   52.4g .

Step-by-step explanation:

(a)   The equation is v = k / m^2     where k is the constant of variation.

When m = 49, v = 640 so   640 = k / 49^2

k = 640 * 49^2

= 1,536,640.

Therefore the relation is v =  1536640/ m^2.

(b) (i)

When m = 36g,  the speed v = 1536640 / 36^2

= 1186 m/s.

(ii)   When the speed is  560 m/s :-

560 = 1536640 / m^2

m^2 = 1536640 / 560

=  2744

mass m = √2744

=  52.4g  

3 0
3 years ago
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