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Lubov Fominskaja [6]
3 years ago
14

Fiona has proved that a function, f(x), is an arithmetic sequence. How did she prove that? A. She showed that an explicit formul

a could be created. B. She showed that a recursive formula could be created. C. She showed that f(n) ÷ f(n - 1) was a constant ratio. D. She showed that f(n) - f(n - 1) was a constant difference.
Mathematics
2 answers:
Step2247 [10]3 years ago
6 0

Answer:

Option D is correct

Step-by-step explanation:

Option D is correct

Being an arithmetic sequence there will be common difference between the consecutive terms

Option A is incorrect because it is not necessary that explicit formula is an arithmetic sequence we can create explicit formula for any sequence

Option B is incorrect because recursive formula can be created for any sequence for geometric series also.

Option C is incorrect because the sequence that has constant ratio is the geometric sequence not an arithmetic sequence.

Ad libitum [116K]3 years ago
5 0

Answer:

D. She showed that f(n) - f(n - 1) was a constant difference.

Step-by-step explanation:

∵ A sequence is called arithmetic if there is constant difference between consecutive numbers,

Thus, option D is correct.

In Explicit formulas, we define each term in a sequence directly,

Thus, there are many sequences other than arithmetic that have explicit formula,

i.e. Option A can not be true.

Now, recursive formula defines the relation between successive terms,

Thus, there are many sequences other than arithmetic that have recursive formula,

i.e. Option B can not be true.

Also, if the ratio between successive terms is constant then the sequence is a Geometric sequence,

A GP can not be an AP,

i.e. Option D can not be true.

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A square measures 17r on each side. Which monomial represents the area of the square?
Eduardwww [97]

Answer:

Area of square = 289r²

Step-by-step explanation:

Given:

Side of square = 17r

Find:

Area of square

Computation:

Area of square = side²

Area of square = (17r)²

Area of square = 289r²

5 0
3 years ago
Which is the equation for the line that has a slope of 12 and passes through the point (3, 20)?
Anna007 [38]

Answer:

the first one

Step-by-step explanation:

y-y1=m(x-x1)

y-20=12(x-3)

y-20+20=12\left(x-3\right)+20

simplify:

y=12x-16

4 0
3 years ago
Which series of transformations results in the image being congruent to the pre-image?
erik [133]
For the element to be congruent only rotations, reflections or translations are allowed to be applied
1)
(x, y) → (x, –y)=reflection
(x, y) → (x + 5, y)=translation
(x, y) → (–x, y)=reflection
->is congruent
2)
(x, y) → (x + 1, y)=translation
(x, y) → (–x, –y)=reflection
(x, y) → (2x, y)=scaling->can't be congruent
3)
(x, y) → (0.5x, 0.5y)=scaling->can't be congruent
(x, y) → (x, –y)
(x, y) → (x, y + 8)
4)
(x, y) → (x – 4, y)=translation
(x, y) → (x, y + 3)=translation
(x, y) → (3x, 3y)=scaling->can't be congruent

so 1) is the only series of transformations with a congruent solution
4 0
3 years ago
Read 2 more answers
Prove that if $w,z$ are complex numbers such that $|w|=|z|=1$ and $wz\ne -1$, then $\frac{w+z}{1+wz}$ is a real number.
mr_godi [17]

Answer:

See proof below

Step-by-step explanation:

Let r=\frac{w+z}{1+wz}. If w=-z, then r=0 and r is real. Suppose that w≠-z, that is, r≠0.

Remember this useful identity: if x is a complex number then x\bar{x}=|x|^2 where \bar{x} is the conjugate of x.

Now, using the properties of the conjugate (the conjugate of the sum(product) of two numbers is the sum(product) of the conjugates):

\frac{r}{\bar{r}}=\frac{w+z}{1+wz} \left(\frac{1+\bar{w}\bar{z}}{\bar{w}+\bar{z}}{\right)

=\frac{(w+z)(1+\bar{w}\bar{z})}{(1+wz)(\bar{w}+\bar{z})}=\frac{w+z+w\bar{w}\bar{z}+z\bar{z}\bar{w}}{\bar{w}+\bar{z}+\bar{w}wz+\bar{z}zw}=\frac{w+z+w+|w|^2\bar{z}+|z|^2\bar{w}}{\bar{w}+\bar{z}+|w|^2z+|z|^2w}=\frac{w+z+\bar{z}+\bar{w}}{\bar{w}+\bar{z}+z+w}=1

Thus \frac{r}{\bar{r}}=1. From this, r=\bar{r}. A complex number is real if and only if it is equal to its conjugate, therefore r is real.

3 0
3 years ago
He has a record contract that Pays him a base rate of $200 a month and then additional $12 for each album that he sells. Last mo
slavikrds [6]

Answer:

He sold a total of 37 albums last month.

Step-by-step explanation:

Given,

Total earned money = $644

Base payment = $200

Additional payment for each album = $12

We have to find the number of albums sold by him.

Solution,

Let the number of albums be 'a'.

Total earned money is the sum of base payment and additional payment for each album multiplied with number of albums sold.

So framing in equation form, we get;

644=200+12a

Subtracting both side by '200' using subtraction property, we get;

200+12a-200=644-200\\\\12a=444

Now dividing both side by '12' using division property, we get;

\frac{12a}{12}=\frac{444}{12}\\\\a=37

Hence he sold a total of 37 albums last month.

3 0
3 years ago
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