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castortr0y [4]
3 years ago
11

What is the unit rate of 1,500 divided by 5

Mathematics
1 answer:
Vesna [10]3 years ago
7 0

300 is going to be the answer

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3x + 4y = 12<br> Convert to slope-intercept form
Zigmanuir [339]

Answer:

y=-3/4x+3

Step-by-step explanation:

subtract 3x from both sides:  4y=-3x+12

Divide both sides by 4:  y=-3/4y+3

4 0
3 years ago
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Which transformation would transform the shaded figure onto the unshaded figure????
Rzqust [24]

Answer: A dilation

Step-by-step explanation:

A dilation is when you change the scale factor of an object to take up more or less space to it into the desired area.

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Please help asap!!! i dont understand it
pshichka [43]

Answer:

a

Step-by-step explanation:

A perpendicular bisector, intersects a line at its mid point and is perpendicular to it.

Calculate slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 7, 1) and (x₂, y₂ ) = (9, 13)

m = \frac{13-1}{9-(-7)} = \frac{12}{9+7} = \frac{12}{16} = \frac{3}{4}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{\frac{3}{4} } = - \frac{4}{3} ←  slope of perpendicular bisector

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

(\frac{x_{1}+x_{2}  }{2}, \frac{y_{1}+y_{2}  }{2} )

using (x₁, y₁ ) = (- 7, 1) and (x₂, y₂ ) = (9, 13) , then

midpoint = ( \frac{-7+9}{2}, \frac{1+13}{2} ) = ( \frac{2}{2}, \frac{14}{2} ) = (1, 7 )

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - \frac{4}{3} , then

y = - \frac{4}{3} x + c ← is the partial equation

To find c substitute the midpoint (1, 7) into the partial equation

7 = - \frac{4}{3} + c ⇒ c = \frac{21}{3} + \frac{4}{3} = \frac{25}{3}

y = - \frac{4}{3} x + \frac{25}{3} ← equation of perpendicular bisector

7 0
3 years ago
What is the height of a parallelogram with a base of 5cm and an area of 45cm2?
Gwar [14]
Height = area / base = 45 / 5  = 9 cm Answer
5 0
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Algebra I / Linear Equations and Graphs
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Answer:

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