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Anni [7]
3 years ago
14

The square of the sum of 7 times x and 3 divided by 4 times the difference of x and 1

Mathematics
1 answer:
mote1985 [20]3 years ago
6 0

Answer:

(7x+3/4*[x-1])^2

Step-by-step explanation:

The square of the sum of 7 times x. and 3 divided by 4 times the difference of x and 1. This would mean that (7x+3/4*[x-1])^2 You would perform x - 1 in the [] first, which is why they are in the extra brackets. The whole thing is squared, so it is all in parenthesis, being squared. It says 3/4 into x-1. This would mean it's multiplying into x-1.

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Plz help me with my geometry asap 50 pts and brainliest NO SCAMMING OR I WILL REPORT
bearhunter [10]

Step-by-step explanation:

1. You already got the first step, where D is the midpoint of AC and AB is congruent to BC, since it's given.

2. AD will be congruent to DC, via the definition of a midpoint (a midpoint is the middle point of a line segment, and it splits the segment into two congruent parts)

3. BD is equal to BD, via reflexive property. ( It's a shared side between the two triangles)

4. that means that ΔADB ≅ΔCDB via SSS rule.

5. ∠ABD ≅∠CDB by CPCTC (corresponding parts of congruent triangles are congruent)

Hope this helps! :)

4 0
2 years ago
Read 2 more answers
The one-time fling! Have you ever purchased an article of clothing (dress, sports jacket, etc.), worn the item once to a party,
Mama L [17]

Answer:

(a)\ P(x = 0) = 0.2725

(b)\ P(x \ge 1) =0.7275

(c)\ P(x \le 2) = 0.8948

Step-by-step explanation:

Given

n = 8 --- 8 friends

p = 15\% --- proportion that one-time fling

This question is an illustration of binomial probability, and it is represented as:

P(X = x) = ^nC_x* p^x * (1 - p)^{n-x}

Solving (a): P(x = 0) --- None has done one time fling

P(x = 0) = ^8C_0* (15\%)^0 * (1 - 15\%)^{8-0}

P(x = 0) = 1* 1 * (1 - 0.15)^{8}

P(x = 0) = 0.85^8

P(x = 0) = 0.2725

Solving (b): P(x \ge 1)

To do this, we make use of compliment rule:

P(x = 0) + P(x \ge 1) =1

Rewrite as:

P(x \ge 1) =1 - P(x = 0)

P(x \ge 1) =1 - 0.2725

P(x \ge 1) =0.7275

Solving (c): P(x\le 2)--- Not more than 2 has one time fling

This is calculated as:

P(x\le 2) = P(x = 0) + P(x =1) + P(x = 2)

We have:

P(x = 0) = 0.2725

P(x = 1) = ^8C_1* (15\%)^1 * (1 - 15\%)^{8-1}

P(x = 1) = 8* (0.15) * (1 - 0.15)^7

P(x = 1) = 0.3847

P(x = 2) = ^8C_2* (15\%)^2 * (1 - 15\%)^{8-2}

P(x = 2) = 28* (0.15)^2 * (1-0.15)^6

P(x = 2) = 0.2376

So:

P(x\le 2) = P(x = 0) + P(x =1) + P(x = 2)

P(x \le 2) = 0.2725 + 0.3847 + 0.2376

P(x \le 2) = 0.8948

4 0
3 years ago
What is the product when you multiply (x2 + 2x - 5) and (x + 3) please answer asap
frozen [14]
Is that supposed to be x squared, or x times 2 in the beginning of the first one?
4 0
2 years ago
Assume the annual day care cost per child is normally distributed with a mean of ​$9000 and a standard deviation of ​$1000. What
Tpy6a [65]

Answer:

65.54% (nearest hundredth)

Step-by-step explanation:

Given:

  • \sf \mu=9000
  • \sf \sigma=1000

\sf X \sim N(\mu, \sigma^2)\implies X \sim N(9000,1000^2)

P(X > 8600) = 1 - P(X ≤ 8600)

                    = 1 - 0.3445782584

                    = 0.6554217416

                    = 65.54%

3 0
2 years ago
What is 50,779 divided by 590? Attach work pretty plz
nignag [31]
50,779/590 is 90.7125 but rounded to 90.71
6 0
3 years ago
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