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N76 [4]
1 year ago
14

Solve for the value of w. * (8w+8)(9w-5)°​

Mathematics
1 answer:
likoan [24]1 year ago
6 0

The solution for the value w is 13 in the equation 8w+8 = 9w-5.

<h3>What is an angle?</h3>

Two rays, referred to as the angle's sides and vertex, come together to form an angle. Angles created by two rays are located in the plane where the rays are located.

Dihedral angles are formed when two planes intersect. The angle formed by the rays lying perpendicular to the two intersecting curves at their point of intersection can also be used to define an angle between two intersecting curves.

Angle is a term used to describe the size of an angle or of a rotation. This metric represents the proportion of a circular arc's length to radius. In the case of a geometric angle, the arc is centred at the vertex and is bound by the sides.

We know that vertical angles of intersection are equal, so here

⇒ (8w+8) = (9w-5)

⇒ 8w+8 = 9w-5

⇒ 9w - 8w = 8 + 5

⇒ w = 13

Angle measure = 8(13)+8

                          = 112°

Learn more about angles

brainly.com/question/25716982

#SPJ13

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A triangle.

Step-by-step explanation:

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The midpoint of line XZ is (2,-5). One endpoint is X(12,-5). Find the coordinates of the other endpoint Z
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Step-by-step explanation:

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3 years ago
Recall that m(t) = (1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500g sample of phosphorus-32 decays
katrin2010 [14]

The question is incomplete, here is the complete question:

Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.

<u>Answer:</u> The half life of the sample of phosphorus-32 is 14.28days^{-1}

<u>Step-by-step explanation:</u>

The equation used to calculate the half life of the sample is given as:

m(t)=m_o(1/2)^{t/h}

where,

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m_o = initial amount of the sample = 500 g

t = time period = 7 days

h = half life of the sample = ?

Putting values in above equation, we get:

356=500\times (\frac{1}{2})^{7/h}\\\\h=14.28days^{-1}

Hence, the half life of the sample of phosphorus-32 is 14.28days^{-1}

7 0
3 years ago
The radius of the circle is increasing at a rate of 2 meters per minute and the sides of the square are increasing at a rate of
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Answer:

Change in area=24\pi-48

Step-by-step explanation:

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Then two given conditions are

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2)ds/dt=1 m/s

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Area of square=s^{2}

Area of circle=\pi r^{2}

Area enclosed=(\pi  r^{2})-s^{2}

dA/dt=2\pir(dr/dt)-2s(ds/dt)

At s=24,and r=6

dA/dt=2(\pi)(6)(2)-2(24)(1)

Change in area=24\pi-48

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Alex787 [66]

Answer:

Choice D

Step-by-step explanation:

QS ≈ TR

they have same direction, sense and magnitude

8 0
3 years ago
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