If the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7
Consider the first odd integer as x
Then the next consecutive odd integer = x+2
The 6 times the second integer= 6(x+2)
= 6x+12
Sum of an integer and 6 times the next consecutive odd integer is 61
Then the equation will be
x + 6x+12 = 61
Add the like terms in the equation
(1+6)x + 12 = 61
7x +12 = 61
Move 12 to the right hand side of the equation
7x = 61-12
7x = 49
x = 49/7
x = 7
The second number is
x+2 = 7+2
= 9
Hence, if the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7
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5/9 * 2*5+4/5
5/9 * 10 + 4/5
5/9 * 14/5
5 * 14/9 * 5
70/9*5
70/45
14/9
1 5/9.
Answer:
Step-by-step explanation:
I assume that the last question should read "cosE"
Before we start to answer, let's get our formulas put in.
4 qt = 1 gal.
1 c = 0.5pt (or 2 cups to 1 pt)
Now that we've gotten the formulas out of the way, let's plug in our numbers.
We have 5 qt.
Since we have 4 qt per gal, let's subtract 4 from 5.
5 - 4 = 1. We have 1 gal (due to having a whole 4) and 1 qt left over.
5 qt = 1 gal 1 qt.
We have 7 c.
Since we have 2 cups per pint, let's divide 7 by 2.
7 / 2 = 3.5
We have 3.5 Pt.
7c = 3.5pt
Your answers are:
1 gal 1 qt
3.5pt
I hope this helps!
