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3 years ago

What is the cube root of 512m^12n15

2 answers:

3 0

∛(512m¹²n¹⁵) = (∛512)*(∛m¹²)(∛n¹⁵)

$\sqrt[3]{m^{12}} =m^{ \frac{12}{3}} =m^{4}
\\ \\ \sqrt[3]{n^{15}} = n^{ \frac{15}{3} } =n^{5}

Answer: 8m^{4}n^{5}.$

Anestetic [448]3 years ago

3 0

Answer: The correct answer is 8m⁴n⁵

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Person to get this question right will get brainliest: If I have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 li

dybincka [34]

Answer:

If i have three moles of a gas at a pressure of 5.6 atm and a volume of 3 liters, what is the temperature ?

We have the following data:

n (number of moles) = 3 moles

P (pressure) = 5.6 atm

V (volume) = 12 L

T (temperature) = ? (in Kelvin)

R (gas constant) = 0.082 atm.L / mol.K

We apply the data above to the Clapeyron equation (gas equation), let's see:

Answer:

The temperature is approximately 205 Kelvin

5 0

3 years ago

Read 2 more answers

Pick the correct description of the line y=-5/3x

Genrish500 [490]

Where are the choices or whatever ~Description s where are they ..?

8 0

3 years ago

Y=-3x+12 Y=-3

Alenkasestr [34]

Well first you substitute -3 for y and then subtract 12 from both sides of the equation and it should look like -15=-3x. Then divide 3 on both sides and you should end up getting 5=x.

4 0

3 years ago

In properties of logarithms, what is log2 25?

spayn [35]

$log_a(b)=c$ $log_a(b)=c$ translates to

$a^c=b$ $a^c=b$
let's say it equals y

$log_2(25)=y$ $log_2(25)=y$
trsnaltes to
$2^y=25$ $2^y=25$
doesn't help us
we can also translate it to
$log_2(5^2)$ $log_2(5^2)$ or $2log_2(5)$ $log_2(5^2)$

not sure what you're looking for

8 0

3 years ago

From base camp, a hiker walks 3.5 miles west and 1.5 miles north. Another hiker walks 2 miles east and 0.5 miles south. To the n

levacccp [35]

Answer:

The hikers are 5.9 miles apart.

Step-by-step explanation:

Let O represents the base camp,

Suppose after walking 3.5 miles west, first hiker's position is A, then after going 1.5 miles north from A his final position is B,

Similarly, after walking 2 miles east, second hiker's position is C then going towards 0.5 miles south his final position is D.

By making the diagram of this situation,

Let D' is the point in the line AB,

Such that, AD' = CD

In triangle BD'D,

BD' = AB + AD' = 1.5 + 0.5 = 2 miles,

DD' = AC = AO + OC = 3.5 + 2 = 5.5 miles,

By Pythagoras theorem,

$BD^2 = BD'^2 + DD'^2$

$BD = \sqrt{2^2 + 5.5^2}=\sqrt{4+30.25}=\sqrt{34.25}\approx 5.9$

Hence, the hikers are 5.9 miles apart.

8 0

3 years ago