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2 years ago

8

a line perpendicular to y=-1/5x+1 and intersects the point (-5,1) what is the equation of this perpendicular line

1 answer:

nikitadnepr [17]2 years ago

3 0

Answer:

Step-by-step explanation:

y = -1/5x + 1

the slope here is -1/5.....a perpendicular line will have a negative reciprocal slope. All that means is flip the slope and change the sign. So our perpendicular slope will have to be 5.....(because I flipped -1/5, making it -5/1, then I switched the sign...making it 5/1 or just 5)

y = mx + b

slope(m) = 5

(-5,1)...x = -5 and y = 1

now we sub and find b, the y int

1 = 5(-5) + b

1 = - 25 + b

1 + 25 = b

26 = b

so ur equation for the perpendicular line is : y = 5x + 26

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