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zzz [600]
3 years ago
8

a line perpendicular to y=-1/5x+1 and intersects the point (-5,1) what is the equation of this perpendicular line

Mathematics
1 answer:
nikitadnepr [17]3 years ago
3 0

Answer:

Step-by-step explanation:

y = -1/5x + 1

the slope here is -1/5.....a perpendicular line will have a negative reciprocal slope. All that means is flip the slope and change the sign. So our perpendicular slope will have to be 5.....(because I flipped -1/5, making it -5/1, then I switched the sign...making it 5/1 or just 5)

y = mx + b

slope(m) = 5

(-5,1)...x = -5 and y = 1

now we sub and find b, the y int

1 = 5(-5) + b

1 = - 25 + b

1 + 25 = b

26 = b

so ur equation for the perpendicular line is : y = 5x + 26

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Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
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<u>Algebra I</u>

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Step-by-step explanation:

<u>Step 1: Define Equation</u>

2(6x + 4) - 6 + 2x = 3(4x + 3) + 1

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Distribute:                                   12x + 8 - 6 + 2x = 12x + 9 + 1
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