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3 years ago

Jorge bought 16 apples for $8.00.

Mathematics

1 answer:

dem82 [27]3 years ago

7 0

Answer:

x=16

y=8.00

8/16=0.5 (50 cents per apple)

y=0.5x+0

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A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard

bulgar [2K]

Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

$\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44$

In point a)

$\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}$

$= \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2$

$value= (1- \frac{1}{k^2}) \times 100 \% =75\%$

In point b)

$\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma \\\\= |(x-\mu)|\leq 2.5 \times 4.44 \\\\ = |(x-\mu)|\leq 1.11 \\\\ = (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)$

In point c)

$\to 99.7 \% \\ lie \ between=28.75 \pm z(.03)\times \sigma \\\\ =28.75\pm 2.97 \times 4.44\\\\=(28.75\pm 13.1)\\\\=(15.65,41.85)\\$

In point d)

using standard normal variate

$x=20.17\\\\ z=-2 \\\\x=37.13\\\\ z=2\\\\\to P(20.17$

8 0

3 years ago

Pls help this is due today :)

Sedaia [141]

Answer:

Left 7 down 6 Then count two spaces left right up and down and draw a circle

Step-by-step explanation:

Your answer is going to be in the bottom left corner, you count 7 vertical lines to the left, then from there you count 6 horizontal lines down. Since the Radius is 2 the diameter is 4. Good luck, if this wasn't helpful enough you can get a graphing calculator for yourself.

5 0

4 years ago

Read 2 more answers

Solve the inequality below. Enter your answer as an inequality, such as x < 2/3

marin [14]

Answer:

Divide each term by -5 and simplify

Step-by-step explanation

-5/-5=1

-5/-80=16

x<16

5 0