Question

Write balanced molecular equation for the reaction between hydrobromic acid and potassium hydroxide.

Answer 1

Reaction of an acid and a base is called a neutralization reaction which forms a salt and water. For the reaction of hydrobromic acid and potassium hydroxide, the products would be bromine potassium bromide and water. The equation would be :

HBr + KOH = KBr + H2O

Answer 2

Answer:

The balanced equation for this neutralization reaction is:

$HBr_{(aq)}+KOH_{(aq)}$ ⇒ $KBr_{(aq)}+H_{2}O_{(l)}$

Explanation:

Hydrobromic acid is a strong acid. It is produced by dissolving hydrogen bromide (HBr) in water. Thus, its phase is aqueous (aq).

Potassium hydroxide is a strong base, usually commercialized as colorless pellets (s), but could be easily dissolved in water to ease the reaction, that is why it will be considered aqueous for this reaction.

The reaction between an acid and a base is called neutralization reaction, and it produces liquid water (l) and salt, as follows:

    $HBr_{(aq)}+KOH_{(aq)}$ ⇒ $KBr_{(aq)}+H_{2}O_{(l)}$

We can check that this equation is balanced since it has the same amount of each element on both sides of the equation:

$HBr_{(aq)}+KOH_{(aq)}$ ⇒ $KBr_{(aq)}+H_{2}O_{(l)}$    

K:   0      +      1       =       1      +      0

Br:   1       +     0       =       1      +      0

H:   1       +     1        =       0     +      2

O:    0      +     1        =       0     +      1