<span>the balanced equation for the reaction is as follows ;
Na</span>₂S + 2AgNO₃ ---> 2NaNO₃ + Ag₂<span>S
stoichiometry of Na</span>₂S to AgNO₃<span> is 1:2
number of AgNO</span>₃<span> moles reacted - 0.315 mol/L x 0.04000L = 0.0126 mol according to molar ratio of 1:2
number of Na</span>₂S moles required are - 1/2 x number of AgNO3 moles reacted Na₂<span>S moles = 0.0126 mol /2 = 0.00630 mol
molarity of Na</span>₂<span>S - 0.260 M
there are 0.260 mol in 1 L
therefore 0.00630 mol are in - 0.00630 mol / 0.260 mol/L
volume of Na</span>₂<span>S required = 0.0242 L
volume of Na</span>₂S required = 24.4 mL
<span>In order to figure out the number of atoms that are present in 2.0 mol of an element, you would multiply Avogadro's number of atoms per mole by 2.0 mole. Avogadro’s is the number of units in one mole of a substance equal to 6.022140857 × 1023.</span>
A.
<span>hydrogen; helium
is the right answer</span>
Answer:
Hi there!
The correct answer is 2.29 x 
molecules
Explanation:
To convert from the moles to molecules:
1 mole = 6.022 x 10²³ molecules
so basically you multiply 3.8 by 6.022 x 10²³
and you get: 2.29 x
