Answer:
following are the solution to the given points:
Step-by-step explanation:
In point a:
calculating unit vector:
the point Q is at a distance h from P(6,6) Here, h=0.1
the value of Q= (5.92928 ,6.07071 )
In point b:
Calculating the directional derivative of at P in the direction of
In point C:
Computing the directional derivative using the partial derivatives of f.
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Answer:
c
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Answer:
The correct option is D
66°
Step-by-step explanation:
Given that ∠PTQ ≅ ∠RTS
The measure of the arc SR = 66°
So ∠RTS = 66°
But also, ∠PTQ ≅ ∠RTS
Therefore ∠PTQ = 66°
and the measure of the arc PQ = ∠PTQ
Therefore, measure of the arc PQ is 66°.
Answer:
tetrahedral
Step-by-step explanation:
According to the valence shell electron pair repulsion theory (VSEPR) the shape of a molecule is dependent on the number of electron pairs on the valence shell of the central atom in the molecule.
The predicted electron pair geometry may sometimes differ from the molecular geometry due to the presence of lone pairs and multiple bonds.
If we consider each nitrogen atom in N2 independently, we will notice that each nitrogen atom has four regions of electron density. Hence the electron pair geometry is tetrahedral.