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vladimir1956 [14]
3 years ago
14

Given f(x) = 2x + 5 and g(x) = 3x + 6

Mathematics
2 answers:
guapka [62]3 years ago
8 0
(f-g)x = 2x + 5 - (3x + 6) =  -x-1
so 
(f-g)(8) = -8-1 = -9
Kryger [21]3 years ago
6 0
I hope this helps you



f(8)=2.8+5=21


g(8)=3.8+6=30


f-g(8)=21-30= -9
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Graph for f(x)=6^6 and f(x)=14^x
zlopas [31]

Graph Transformations

There are many times when you’ll know very well what the graph of a

particular function looks like, and you’ll want to know what the graph of a

very similar function looks like. In this chapter, we’ll discuss some ways to

draw graphs in these circumstances.

Transformations “after” the original function

Suppose you know what the graph of a function f(x) looks like. Suppose

d 2 R is some number that is greater than 0, and you are asked to graph the

function f(x) + d. The graph of the new function is easy to describe: just

take every point in the graph of f(x), and move it up a distance of d. That

is, if (a, b) is a point in the graph of f(x), then (a, b + d) is a point in the

graph of f(x) + d.

As an explanation for what’s written above: If (a, b) is a point in the graph

of f(x), then that means f(a) = b. Hence, f(a) + d = b + d, which is to say

that (a, b + d) is a point in the graph of f(x) + d.

The chart on the next page describes how to use the graph of f(x) to create

the graph of some similar functions. Throughout the chart, d > 0, c > 1, and

(a, b) is a point in the graph of f(x).

Notice that all of the “new functions” in the chart di↵er from f(x) by some

algebraic manipulation that happens after f plays its part as a function. For

example, first you put x into the function, then f(x) is what comes out. The

function has done its job. Only after f has done its job do you add d to get

the new function f(x) + d. 67Because all of the algebraic transformations occur after the function does

its job, all of the changes to points in the second column of the chart occur

in the second coordinate. Thus, all the changes in the graphs occur in the

vertical measurements of the graph.

New How points in graph of f(x) visual e↵ect

function become points of new graph

f(x) + d (a, b) 7! (a, b + d) shift up by d

f(x) Transformations before and after the original function

As long as there is only one type of operation involved “inside the function”

– either multiplication or addition – and only one type of operation involved

“outside of the function” – either multiplication or addition – you can apply

the rules from the two charts on page 68 and 70 to transform the graph of a

function.

Examples.

• Let’s look at the function • The graph of 2g(3x) is obtained from the graph of g(x) by shrinking

the horizontal coordinate by 1

3, and stretching the vertical coordinate by 2.

(You’d get the same answer here if you reversed the order of the transfor-

mations and stretched vertically by 2 before shrinking horizontally by 1

3. The

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74

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5 0
3 years ago
Six and forty-two ten-thousandths as a decimal
sergey [27]

Answer:

6.0042

Step-by-step explanation:

6 and forty-two ten-thousandths as a decimal.

mixed number : 6\frac{42}{10,000}

decimal : 6.0042

7 0
3 years ago
Please help Need help
Anettt [7]
This problem can be readily solved if we are familiar with the point-slope form of straight lines:
y-y0=m(x-x0) ...................................(1)
where 
m=slope of line
(x0,y0) is a point through which the line passes.

We know that the line passes through A(3,-6), B(1,2)

All options have a slope of -4, so that should not be a problem.  In fact, if we check the slope=(yb-ya)/(xb-xa), we do find that the slope m=-4.

So we can check which line passes through which point:

a. y+6=-4(x-3)
Rearrange to the form of equation (1) above,
y-(-6)=-4(x-3)  means that line passes through A(3,-6) => ok

b. y-1=-4(x-2) means line passes through (2,1), which is neither A nor B
   ****** this equation is not the line passing through A & B *****

c. y=-4x+6  subtract 2 from both sides (to make the y-coordinate 2)
   y-2 = -4x+4, rearrange
   y-2 = -4(x-1)  
   which means that it passes through B(1,2), so ok

d. y-2=-4(x-1)
   this is the same as the previous equation, so it passes through B(1,2), 
   this equation is ok.

Answer: the equation y-1=-4(x-2) does NOT pass through both A and B.
   
8 0
3 years ago
What is the solution to the system of equations?
Mazyrski [523]
Y= <span><span><span>−25 
   --------- x
       8
H
  O
     P
       E
              THIS HELPS!</span></span></span>
8 0
3 years ago
Please help.
Luba_88 [7]

Answer:

6.5%

Step-by-step explanation:

The original price of the ticket was 100% of the price of the ticket.

The 15% coupe reduced the price to 85% of the price of the ticket.

The 10% fee on the discounted price adds 10% of 85% to 85%, so it adds 8.5% to 85%. By adding the fee he is at 93.5% of the original price.

100% - 93.5% = 6.5%

The overall percent off compared to the original price was 6.5%.

Answer: 6.5%

4 0
2 years ago
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