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Grace [21]
3 years ago
7

Helpppppppppp aasapppp

Mathematics
2 answers:
Paha777 [63]3 years ago
8 0

Answer:

2

Step-by-step explanation:

Convert mixed fraction to improper fraction

-2\frac{2}{3}=-\frac{8}{3}\\\\\\-1\frac{1}{3}=-\frac{4}{3}

-2\frac{2}{3} ÷ -1\frac{1}{3} = \frac{-8}{3} ÷ -\frac{4}{3}

                  =-\frac{8}{3}*-\frac{3}{4}\\\\\\=2 *1 \\\\= 2

dimaraw [331]3 years ago
7 0

Answer:

2

Step-by-step explanation:

Simplify the following:

(-(2 + 2/3))/(-(1 + 1/3))

(-(2 + 2/3))/(-(1 + 1/3)) = (-1)/(-1)×(2 + 2/3)/(1 + 1/3) = (2 + 2/3)/(1 + 1/3):

(2 + 2/3)/(1 + 1/3)

Put 1 + 1/3 over the common denominator 3. 1 + 1/3 = 3/3 + 1/3:

(2 + 2/3)/(3/3 + 1/3)

3/3 + 1/3 = (3 + 1)/3:

(2 + 2/3)/((3 + 1)/3)

3 + 1 = 4:

(2 + 2/3)/(4/3)

Put 2 + 2/3 over the common denominator 3. 2 + 2/3 = (3×2)/3 + 2/3:

((3×2)/3 + 2/3)/(4/3)

3×2 = 6:

(6/3 + 2/3)/(4/3)

6/3 + 2/3 = (6 + 2)/3:

((6 + 2)/3)/(4/3)

6 + 2 = 8:

(8/3)/(4/3)

Multiply the numerator by the reciprocal of the denominator, (8/3)/(4/3) = 8/3×3/4:

(8×3)/(3×4)

(8×3)/(3×4) = 3/3×8/4 = 8/4:

8/4

The gcd of 8 and 4 is 4, so 8/4 = (4×2)/(4×1) = 4/4×2 = 2:

Answer: 2

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If 2x^2+2x-8 is the quotient when x+3 divides P(x), which of th3 following is the quotient when 2x+6 divides p(x)?
maria [59]

Answer: A

2x^2+2x-8 is the quotient when x+3 divides P(x)

=> P(x) = (2x² + 2x -8)(x + 3) = 2(x² + x - 4)(x + 3) = (x² + x - 4) (2x + 6)

=> the quotient when 2x+6 divides p(x) is x² + x - 4

Step-by-step explanation:

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3 years ago
The Springer Dog Food Company makes dry dog food from two ingredients. The two ingredients (A and B) provide different amounts o
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Answer:

a) Objective function (minimize cost):

C=0.50A+0.20B

Restrictions

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Vitamins per pound: 4A+8B\leq 6

Non-negative values: A,B\geq0

b) Attached

c) The optimum solution (minimum cost) is 0 pounds of ingredient A and 0.75 pounds of ingredient B. The cost is $0.15 per ration.

d) The optimum solution changes. The cost is now 0 pounds of ingredient A and 0.625 pounds of ingredient B. The cost is $0.125 per ration.

Step-by-step explanation:

a) The LP formulation for this problem is:

Objective function (minimize cost):

C=0.50A+0.20B

Restrictions

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Vitamins per pound: 4A+8B\leq 6

Non-negative values: A,B\geq0

b) The feasible region is attached.

c) We have 3 corner points. In one of them lies the optimal solution.

Corner A=0 B=0.75

C=0.50*0+0.20*0.75=0.15

Corner A=0.5 B=0.5

C=0.50*0.5+0.20*0.5=0.35

Corner A=0.75 B=0

C=0.50*0.75+0.20*0=0.375

The optimum solution (minimum cost) is 0 pounds of ingredient A and 0.75 pounds of ingredient B. The cost is $0.15 per ration.

d) If the company requires only 5 units of vitamins per pound rather than 6, one of the restrictions change.

The feasible region changes two of its three corners:

Corner A=0 B=0.625

C=0.50*0+0.20*0.625=0.125

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C=0.50*0.583+0.20*0.333=0.358

Corner A=0.75 B=0

C=0.50*0.75+0.20*0=0.375

The optimum solution changes. The cost is now 0 pounds of ingredient A and 0.625 pounds of ingredient B. The cost is $0.125 per ration.

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Step-by-step explanation:

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