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ollegr [7]
3 years ago
15

A pot of stew is placed on a stove to heat. The temperature of the liquid reaches 170°F, and then the pot is taken off the burne

r and placed on a kitchen counter. The temperature of the air in the kitchen is 76°F.
If k = 0.34, the temperature of the liquid after 7 hours will be

ºF. (Hint: Use Newton’s cooling model.)
Mathematics
1 answer:
belka [17]3 years ago
7 0

Answer:

T =84.7\°F

Step-by-step explanation:

Newton's cooling model is:

T(t) =T_0 + (T_i-T_0)e^{-kt}

Where

t is the time in hours

T_0 is the ambient temperature

T_i is the initial temperature of the body

k=0.34

We know that:

T_0=76\°F

T_i=170\°F

Then after 7 hours the temperature of the liquid will be:

T(7) =76 + (170-76)e^{-0.34(7)}

T =84.7\°F

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