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AfilCa [17]
3 years ago
14

Can someone plz correct me ?

Mathematics
1 answer:
Verizon [17]3 years ago
5 0
I would guess that the answer would be A) likely but it not it would probably be C) certain
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Pls help, i need help i dont understand
Svet_ta [14]

Answer:

I think it's 140 not sure

5 0
2 years ago
Paige launched a ball using a catapult she built. The height of the ball (in meters above the ground) ttt seconds after launch i
agasfer [191]

Answer:

1) Factor form : h(t)=-5t(t-8)

2) 8 second after launch.

Step-by-step explanation:

The height of the ball (in meters above the ground) t seconds after launch is modeled by

h(t)=-5t^2+40t

To find the time when ball hit the ground, we need to find the factor form of the given function.

h(t)=-5t(t-8)

When ball hi the ground, then height of the ball from the ground is 0.

h(t)=0

-5t(t-8)=0

Using zero product property, we get

-5t=0\Rightarrow t=0

t-8=0\Rightarrow t=8

Ball hit the ground at t=0 and t=8. It means ball hit the ground in starting and 8 second after launch.

5 0
3 years ago
Find a degree 3 polynomial whose coefficient of x^3 equal to 1. The zeros of this polynomial are -5, -4i, and 4i. Simplify your
borishaifa [10]

Answer:

x^3+5x^2+16x+80

Step-by-step explanation:

You know that you can write your polynom this way : (x-r1)(x-r2)(x-r3) with r1,r2 and r3 the roots so you get :

(x+5)(x+4i)(x-4i)

Simplify (x+4i)(x-4i) with the formula (a-b)(a+b)=a²-b²

so you have (x^2+16)=(x+4i)(x-4i)

Your polynom looks like this :

(x^2+16)(x+5) just expand it

and you get x^3+5x^2+16x+80

7 0
2 years ago
Find the gradient of the line segment between the points (0,6) and (2,16).
maks197457 [2]

Answer:

  5

Step-by-step explanation:

The gradient is the ratio of the change in y to the change in x:

  m = ∆y/∆x = (16 -6)/(2 -0) = 10/2 = 5

The gradient of the line segment is 5.

6 0
3 years ago
Plz help me solve this problem
zhannawk [14.2K]
I'm answer for u is 240 cubic units=b
3 0
3 years ago
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