The root -2 leads to the factor (x+2). The other 2 factors are (x-5) and (x-6).
Then the poly is f(x) = (x+2)(x-5)(x-6).
Cosine 65 = 12 / x
0.4226183 = 12 / x
x = 12 / 0.4226183
<span>
<span>
<span>
x = 28.39441</span></span></span>
So, I'd say you are correct.
Answer:
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
Step-by-step explanation:
Given;
Standard deviation r= 25mg
Width of confidence interval w= 10mg
Confidence interval of 95%
Margin of error E = w/2 = 10mg/2 = 5mg
Z at 95% = 1.96
Margin of error E = Z(r/√n)
n = (Z×r/E)^2
n = (1.96 × 25/5)^2
n = (9.8)^2
n = 96.04
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
1. -48v-5/45 2.44-r/2 3. x=2
5x-2x=7x+2x-24
3x = 9x -24
3x - 9x = -24
-6x = -24
x = -24/-6
x = 4
