The mass of a textbook is about 1.25 kilograms. About how many pounds is it?

A Brainliest for the correct answer

Kaylis [27]

The answer to 7 is 359.42

5 0

3 years ago

In mathematics given that x=L2-L1/L1(O2-O1).

Assoli18 [71]

Answer:

1. L1 = $\frac{L2}{X(O2 -O1)}$

2. O2 = $\frac{L2 - L1(1 + XO1)}{XL1}$

Step-by-step explanation:

Given: x = $\frac{L2 - L1}{L1(O2 -O1)}$

1. To make L1 the subject of formula;

x = $\frac{L2 - L1}{L1(O2 -O1)}$

cross multiply to have;

L2 - L1 = xL1(O2 - O1)

collect like terms,

L2 = xL1(O2 - O1) + L1

factorize the right hand side;

L2 = L1[x(O2 - O1)]

L1 = $\frac{L2}{X(O2 -O1)}$

2. To make O2 the subject of formula;

x = $\frac{L2 - L1}{L1(O2 -O1)}$

cross multiply to have;

L2 - L1 = xL1(O2 - O1)

open the bracket to have;

L2 - L1 = xL1O2 - xL1O1

⇒ xL1O2 = L2 - L1 + xL1O1

O2 = $\frac{L2-L1 + XL1O1}{XL1}$

= $\frac{L2 - L1(1 + XO1)}{XL1}$

4 0

3 years ago

Put the equation y = x^2 + 26 x + 160 into the form y = ( x − h )^2 + k :

KATRIN_1 [288]

Put the equation $y = x^2 + 26 x + 160$ into the form y = ( x − h )^2 + k

Given equation is $y = x^2 + 26 x + 160$

We apply completing the square method

we take coefficient of middle term and then divide by 2 and then square it

coefficient of middle term is 26

Divide by 2, it becomes 13

then we square it (13)^2 = 169

Add and subtract 169

$y = x^2 + 26 x +169 - 169 + 160$

$y = x^2 + 26 x +169 - 9$

$y = (x + 13)^2 - 9$

We got the equation in vertex form

6 0

3 years ago

Read 2 more answers

| 9. The distance between Town A and Town B was 108 km. A car and a van left Town A at 12 00 for Town B. On reaching Town B, the

Westkost [7]

Answer:

a) Time until both vehicles meet is 1.5 hours after starting at noon. That makes it 1:30PM.

b) Average speed of car is 84 km/h

Step-by-step explanation:

A -----------------------z------------B

Left Speed(km/h) Time

Car: 12PM X

Van: 12PM 60

Car/Van

DistanceCar AB + z

DistanceVan Az

Ratio: (AB+z)/Az = 7/5

Time until both meet = T (in hours)

Distance Car: xT

Distance Van: 60T

====

xT = AB + z

60T = Az

---

(xT/60T)= (7/5)

x = 60(7/5)

x = 84 km/h

=====

Time for car to reach B is: time (hr) = 108 km/(84 km/h)

time = 1.286 hours

Distance for at 1.289 hours is: distance (km) = (60 km/h)*(1.286 h)

distance = 77.14 km

At 1.286 hours, the car reverses direction. The van is (108 km - 77.14 km) or 30.86 km away.

Add the distances travelled by both vehicles after the car reverses direction at 1.286 hours. The sum will be 30.86 km when they meet, at time of T.

Car Distance + Van Distance = 30.86 km

T(84 km/h) + t(60 km)

They meet when they are 0 km apart, which can be modeled with the following equation:

Van travel Distance - Car Travel Distance = 0 starting at 1.286 hr.

Let t be the time after 1.286 hours that both vehicles meet/collide.

t*(60 km/h) + t(84 km/h) = 30.86 km

t(60+84) = 30.86 km

t(144 km/h) = 30.86 km

t = 0.2143 hr

Total time until the car and van meet is 1.286 hr + 0.2143 hr for a total of 1.50 hours.

=================

a) Time until both vehicles meet is 1.5 hours after starting at noon. That makes it 1:30PM.

b) Average speed of car is 84 km/h

==============

CHECK

Is the ratio of the distance travelled by the car and the van until they meet in the ratio of 7/5?

Car distance is (1.5 hr)(84 km/h) = 126 km

Van distance is (1.5 hr)(60 km/h) = 90.0 km

Ratio is 126/90 or 1.4

Ratio of 7/5 is 1.4

YES

3 0

2 years ago

7(5 - 6x) - 4x =-8 + 35 show work

Sever21 [200]

This is the work and the answer is 4/23 or (in decimal form) 0.17391304

5 0

3 years ago