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pishuonlain [190]
3 years ago
14

Show that x⁵²-21x+20 is divisible by x− 1.

Mathematics
1 answer:
SashulF [63]3 years ago
4 0

Answer

given equation,

x⁵²-21 x+20

A number to be divisible by the another number means that on dividing the remainder should be zero.

if x⁵²-21 x+20 is divisible by x− 1 means that x-1 should completely divide the equation.

 so,

      x -1 = 0

       x = 1

x⁵²-21 x+20 to be divisible it should be equal to zero when x = 1

putting x = 1

= (1)⁵²-21 (1)+20

= 1 - 21 + 20

= 21 -21

= 0

hence x = 1 is the root of the equation

so, x⁵²-21 x+20 is divisible by x− 1.

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Find the discriminant of x2-6x -10 = 0, and determine the number of real solutions of the equation.​
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Answer:

76

2 real solutions

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

Standard Form: ax² + bx + c = 0

Discriminant: b² - 4ac

  • Positive - 2 solutions
  • Equal to 0 - 1 solution
  • Negative - No solutions/Imaginary

Step-by-step explanation:

<u>Step 1: Define</u>

x² - 6x - 10 = 0

<u>Step 2: Identify Variables</u>

<em>Compare quadratic.</em>

x² - 6x - 10 = 0 ↔ ax² + bx + c = 0

a = 1, b = -6, c = -10

<u>Step 3: Find Discriminant</u>

  1. Substitute in variables [Discriminant]:                                                            (-6)² - 4(1)(-10)
  2. [Discriminant] Evaluate exponents:                                                                36 - 4(1)(-10)
  3. [Discriminant] Multiply:                                                                                    36 + 40
  4. [Discriminant] Add:                                                                                          76

This tells us that our quadratic has 2 real solutions.

8 0
2 years ago
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