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frosja888 [35]
3 years ago
15

Sasha order 3/5 of a pound of cheese .Each slice of cheese weighs 0.15 pounds. Enter the number of slices of cheese that Sasha w

ill receive
Mathematics
1 answer:
lapo4ka [179]3 years ago
3 0

Answer:

4. slices

Step-by-step explanation:

because If you turn 3/5 in to a decimal you get 0.6 and each slice of cheese weighs 0.15 so you do 0.6 divided by 0.15

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Given that f(x) = 6x + 2 and g(x) =2x+4 over 5 solve for g(f(1))
Lady bird [3.3K]
F(1)=6(1)+2
= 6+2
=8

g(f(1))= 2x/5 +4/5
= 2(8)/5 +4/5
= 16/5 +4/5
= 20/5
=4
6 0
4 years ago
What is the missing statement in step 3 of the proof? mAngle1 = mAngle2 mAngle1 + mAngle2 = 90° mAngle2 = mAngle3 mAngle2 + mAng
zalisa [80]

Answer:

answer is 90

if m^2=m^3

then, 90+90=180

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The sum of four consecutive odd integers is three more than five times the least of the integers. Find the integers.
Olegator [25]

Answer:

<h3>              9, 11, 13, 15</h3>

Step-by-step explanation:

{k - some integer}

2k+1  - the first odd integer (the least)

5(2k+1)  - five times the least

5(2k+1)+3 -<u> three more than five times the least</u>

2k+1+2 = 2k+3  - the odd integer consecutive to 2k+1

2k+3+2 = 2k+5  - the next odd consecutive integer (third)

2k+5+2 = 2k+7  - the last odd consecutive integer (fourth)

2k+1+2k+3+2k+5+2k+7 - <u>the sum of four odd consecutive integers</u>

2k+1 + 2k+3 + 2k+5 + 2k+7 = 5(2k+1) + 3

8k + 16 = 10k + 5 + 3

     - 10k       -10k

-2k + 16 = 8

     -16       - 16    

      -2k = -8  

    ÷(-2)    ÷(-2)  

      k = 4

2k+1 = 2•4+1 = 9

2k+3 = 2•4+3 = 11

2k+5 = 2•4+5 = 13

2k+7 = 2•4+7 = 15  

Check: 9+11+13+15 = 48;  48-3 = 45;  45:5 = 9 = 2k+1

4 0
3 years ago
On Tuesday a local ice cream truck sold a combined total of 492 ice cream sandwiches and sprites. the number of sandwiches sold
DiKsa [7]
Answer: 164

Reasoning: you would need to divide 492 by 3 to get the number of sprites seeing that the sandwiches are 3 times as much as the amount of sprites sold.

I hope that helped
7 0
3 years ago
Please help me solve this 200(20)^x&gt;500x+400
s2008m [1.1K]
Hi there!

200(20)^x > 500x + 400

Let's find the critical points of the inequality

200(20^x) = 500x + 400

Now we can divide both sides by 200

(200(20^x))/200 = (500x + 400)/200

20x^x = 5/2 x + 2

There are no critical points.

Thus,

The answer is: No solution

As always, it is my pleasure to help students like you.

6 0
4 years ago
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