Which statement is true about the graphs of the two lines y =

Identify the transformation that occurred in ABC and A'B'C'.

Brilliant_brown [7]

Answer:baka senpai

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A landscaper needs 348 pounds of plant food. He has 114 pounds in his truck, and another 46 pound at his shop.

Black_prince [1.1K]

Answer:

$\frac{19}{12}\ pounds$

or

$1\frac{7}{12}\ pounds$

Step-by-step explanation:

<u><em>The correct question is </em></u>

A landscaper needs 3 4/8 pounds of plant food. He has 1 1/4 pounds in his truck, and another 4/6 pound at his shop. How many more pounds of plant food does the landscaper need?

Let

x ----> the additional pounds of plant food needed for the landscaper

we know that

The additional pounds of plant food needed for the landscaper plus the pounds in his truck plus the pounds in his shop must be equal to the total pounds of plant food needed

so

The linear equation that represent this problem is

$x+1\frac{1}{4}+\frac{4}{6}=3\frac{4}{8}$

Convert mixed number to an improper fractions

$1\frac{1}{4}=1+\frac{1}{4}=\frac{4*1+1}{4}=\frac{5}{4}$

$3\frac{4}{8}=3+\frac{4}{8}=\frac{3*8+4}{8}=\frac{28}{8}=\frac{14}{4}$

Substitute in the expression above

$x+\frac{5}{4}+\frac{4}{6}=\frac{14}{4}$

solve for x

Multiply by (4*6) both sides to remove the fractions

$24x+30+16=84$

Combine like terms left side

$24x+46=84$

subtract 46 both sides

$24x=84-46$

$24x=38$

Divide by 24 both sides

$x=\frac{38}{24}\ pounds$

simplify

$x=\frac{19}{12}\ pounds$

Convert to mixed number

$\frac{19}{12}\ pounds=\frac{12}{12}+\frac{7}{12}=1\frac{7}{12}\ pounds$

4 0

3 years ago

Can you please help me list the forms As_,_ and limits

Anastasy [175]

Given the function:

$f(x)=\frac{2x+1}{x}$

First, the graph of the function will be as shown in the following figure:

For the given rational function, we will find the following:

Domain = ( -∞, 0 ) ∪ ( 0, ∞ )

Range = ( -∞, 2) ∪ (2, ∞ )

Increasing = Φ

Decreasing = ( -∞, 2) ∪ (2, ∞ )

All asymptotes:

Vertical asymptote: x = 0

Horizontal Asymptote: y = 2

All limits:

$\begin{gathered} \lim _{x\rightarrow-\infty}f(x)=2 \\ \lim _{x\rightarrow\infty}f(x)=2 \\ \lim _{x\rightarrow0^-}f(x)=-\infty \\ \lim _{x\rightarrow0^+}f(x)=\infty \end{gathered}$