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3 years ago

Which inequality is shown in the graph below?

Mathematics

1 answer:

Leto [7]3 years ago

6 0

Answer:

B. y<2x-2

Step-by-step explanation:

Hope that helps!

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What is the first step to solve the equation A. Square both sides of the equation. B. Add 5 to both sides of the equation. Squar

jekas [21]

Hi :)

I'd start by adding 5 to both sides of the equation. That would make the equation easier.

$\boldsymbol{\sqrt{2x}-5=3}}$

$\boldsymbol{\sqrt{2x}=2}$

The next step is to get rid of the radical sign.

Which operation will undo the square root? Squaring.

So that's why we square both sides:

$\boldsymbol{2x=4}$

And Now we just divide both sides by 2

$\boldsymbol{x=2}$

~ $\textit{\textbf{Learn More; Work Harder}}$ ~

:)

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2 years ago

Which recursive formula can be used to determine the total amount of time spent making hats based on the total amount of time sp

Harrizon [31]

I think the answer is A

4 0

3 years ago

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In percent of change what is 10 to 20

djyliett [7]

I think it may either be 10 or 100.. do you have options to choose from?

5 0

3 years ago

Expand and simplify x(x + 2)(x + 4)

babymother [125]

Answer:

Step-by-step explanation:

Comment

Expand the second and 3rd factors first. Then worry about the x.

Solution

x(x + 2)(x + 4)

first: x * x = x^2

Outside: 4*x = 4x

Inside: 2*x = 2x

Last: 2*4 = 8

Combine

x^2 + 4x + 2x + 8

x^2 + 6x + 8

Now is the time to worry about the extra x

x(x^2 + 6x + 8)

remove the brackets.

x*x^2 + x*6x + 8*x

Combine

Answer: x^3 + 6x^2 + 8x

5 0

2 years ago

Mr. Walker gave his class the function f(x) = (x + 3)(x + 5). Four students made a claim about the function. Each student’s clai

stich3 [128]

Answer:

Stephen's claim is correct.

Step-by-step explanation:

The given function is

$f(x)=(x+3)(x+5)$

Put x=0 to find the y-intercepts.

$f(0)=(0+3)(0+5)=3\times 5=15$

The y-intercept of the function is at (0,15). It means jeremiah's statement is incorrect.

Put f(x)=0, to find the x-intercept.

$0=(x+3)(x+5)$

$x+3=0\Rightarrow x=-3$

$x+5=0\Rightarrow x=-5$

The x-intercepts are at (-3,0) and (-5,0). It means Lindsay's statement is incorrect.

$f(x)=(x+3)(x+5)$

$f(x)=x^2+8x+15$

$f(x)=x^2+8x+15+16-16$

$f(x)=(x^2+8x+16)-1$

$f(x)=(x+4)^2-1$ .... (1)

The vertex form of a parabola is

$f(x)=(x-h)^2+k$ .... (2)

Where, (h,k) is vertex.

From (1) and (2) it is clear that the vertex of the parabola is (-4,-1), Stephen's claim is correct.

The midpoint between the x-intercepts is

$(\frac{-3-5}{2},\frac{0+0}{2})=(-4,0)$

The midpoint between the x-intercepts is at (-4, 0). It means Alexis's statement is incorrect.

3 0

3 years ago

Read 2 more answers