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3 years ago

Evaluate. –1.65 + (–3.4)

1 answer:

6 0

Hey there!

This seems like a algebraic expression

SO,
Remember: negative and negative = positive
positive and positive = positive
positive and negative = negative
negative and positive = negative

In this problem we will be doing negative and negative so that means our answer will be a negative

Firstly, lets line up our decimals to solve this problem (once when you do that , you can solve it easier)

$-1.65 
\\ +
\\ (-3.4)
$

Answer: $-5.05$

Good luck on your assignment and enjoy your day

~ $LoveYourselfFirst:)$

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Prefixes, roots, and suffixes are examples of _____

mojhsa [17]

Answer:

The correct answer should be : Word parts

Step-by-step explanation:

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2 years ago

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How do you do -19+C/3=8 can someone teach how to solve this problem?

ki77a [65]

You're looking for c, so you want to isolate it or get it by itself. To get rid of the /3 you multiply since the opposite of division is multiplication and to get rid of it, you do the opposite (like -9 you would add 9 to get it to 0). Now you are left with -19+c = 24 (the 24 is 8*3 because what you do to one side you do to the other. Now you get c by itself so you add 19 to both sides which leaves you with C= 43. Sorry if this was confusing!

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3 years ago

Irina has 6 tubs of yogurt she wants to scoop it all into bowls each bowl holds 1/4 tub of yogurt which division equation can be

elena55 [62]

In order to find the answer, you can use-

1/4x=6

In order to get the answer, you multiply 6 by the denominator.

6x4=24

Then, you'd divide the solution of that part by the numerator.

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Therefore, the final answer would be 24.

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3 years ago

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A new car is purchased for 17000 dollars. The value of the car depreciates at 12.25% per year. What will the value of the car be

Scilla [17]

Answer:

$P(t=14) = 17000 (1-0.1225)^{14}= 2728.404$

Step-by-step explanation:

for this case we have the following model for the cost of the car:

$P(t) = P_o (1-r)^t$

Where $P_o$ is the initial amount on this case 17000, t the amount of years after the initial year and r the depreciation rate on this case:

$r= \frac{12.25}{100}=0.1225$

And for t =14 we can replace into the equation and we got:

$P(t=14) = 17000 (1-0.1225)^{14}= 2728.404$

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3 years ago

the sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger

Reil [10]

<h2>Answer:</h2>

$x\geq 3 \ and \ x+1 \geq 4$

<h2>Step-by-step explanation:</h2>

The question in this problem is:

<em>The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger. What are the numbers?</em>

<em />

First of all, let's name the first variable $x$ which is the smaller number. Accordingly, the lager number will be $x+1$ given that those numbers are consecutive. On the other hand<em> at most </em>conveys the idea of an inequality, which is:

$\leq \\ which \ means \ less \ than$

So:

1. The sum of 2 consecutive integers can be written as:

$v+(v+1)$

2. Nine times the smaller and 5 times the larger can be written as:

$9v-5(v+1)$

Finally, the whole statement:

The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger:

$x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\$

$x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\ \frac{6}{2} \leq \frac{2x}{2} \\ \\ 3 \leq x \\ \\ x\geq 3 \\ \\ and \\ \\ x+1 \geq 4$

The two numbers are:

$x\geq 3 \ and \ x+1 \geq 4$

6 0

3 years ago