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UNO [17]
3 years ago
11

Sixteen socks are put into pairs. how many pairs are there

Mathematics
2 answers:
GuDViN [60]3 years ago
7 0

if you have 16 socks then you will have 8 pairs of 2.

16 / 2 = 8

answer is 8

Liono4ka [1.6K]3 years ago
7 0

Answer:

16÷2=8pairs

Step-by-step explanation:

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6 0
3 years ago
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A square fits exactly inside a circle with each vertices being on the circumference of the circle. The square has a side length
GarryVolchara [31]

Answer:

Therefore,

The value of x is 5.97 cm.

Step-by-step explanation:

Given:

Let the length of side of Square be "x" cm'.

Radius of Circle be "r"

Area of Circle = 56 cm squared

pi = 3.14

To Find:

x = ?

Solution:

We know Area of Circle is given by,

\textrm{Area of Circle}=\pi r^{2}

Substituting the values we get

56=3.14\times r^{2}\\r^{2}=17.83\\Square\ Rooting\\r=\sqrt{17.83}=4.22\ cm

We have, a square fits exactly inside a circle with each vertices being on the circumference of the circle,

Vertex Angle of a Square is 90°.

In a Circle Diameter Subtends a Right angle,

So it's Diagonal will be the Diameter,

Diagonal =Diameter

Diameter=2\times Radius

Substituting the values we get

Diameter=2\times 4.22=8.44\ cm

Therefore,

Diagonal = 8.44\ cm

Also we know that,

Length of Diagonal of a Square for side "x" is given by,

Diagonal=\sqrt{2}\times x

Substituting the values we get

x=\dfrac{8.44}{\sqrt{2}}=5.967\approx 5.97\ cm

Therefore,

The value of x is 5.97 cm.

3 0
4 years ago
Select the favorable outcomes for rolling a five on the first roll.<br><br><br> Please help.
tia_tia [17]

A 1/6% chance because there are six sides and 5 is one of them

8 0
3 years ago
20p and brainliest for helping me, please!!!!!!!!!!!
BaLLatris [955]
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4 0
3 years ago
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Simplify.<br> Rewrite the expression in the form b^n<br><br> (b^3)^2
Alexxandr [17]

Step-by-step explanation:

a^n={\underbrace{a\cdot a\cdot a\cdot...\cdot a}_{n}

<h2>METHOD 1.</h2>

\left(b^3\right)^2=\underbrace{b^3\cdot b^3}_{2}=\underbrace{b\cdot b\cdot b}_{3}\cdot\underbrace{b\cdot b\cdot b}_{3}=\underbrace{b\cdot b\cdot b\cdot b\cdot b\cdot b}_{6}=b^6

<h2>METHOD 2.</h2>

\left(b^3\right)^2=\underbrace{b^3\cdot b^3}_{2}=b^{3+3}=b^6\qquad\text{used}\ a^n\cdot a^m=a^{n+m}

<h2>METHOD 3.</h2>

\left(b^3\right)^2=\left(\underbrace{b\cdot b\cdot b}_{3}\right)^2=b^2\cdot b^2\cdot b^2=b^{2+2+2}=b^6\\\text{used}\ (ab)^n=a^nb^n,\ a^n\cdot a^m=a^{n+m}

<h2>METHOD 4.</h2>

\left(b^3\right)^2=b^{3\cdot2}=b^6\qquad\text{used}\ \left(a^n\right)^m=a^{nm}

5 0
3 years ago
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