The total area under the curve must equal 1. Let the value of the density curve be x. Then 10x = 1. Therefore x = 1/10 or 0.1.
The correct answer is D. 0.1.
4(x -2) +(y +5) = 0 . . . . . an equation
4x +y = 3 . . . . . . . . . . . . the equation in standard form
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A graph can be seen at
https://www.desmos.com/calculator/3ct9gfxclj
F = t ⇨ df = dt
dg = sec² 2t dt ⇨ g = (1/2) tan 2t
⇔
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt
u = 2t ⇨ du = 2 dt
As integral of tan u = - ln (cos (u)), you get :
integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer
Given :
Challenge given is to volunteer for about 1 1/2 hours per week .
Autum did at a rate of 6 3/4 hours per week .
To Find :
The comparison ( ratio ) her volunteers rate with the challenge rate .
Solution :
Simplifying challenge rate in in normal fraction , 
.
Also , simplifying her rate , 
.
Now , ratio of his work by challenge is :
Therefore , the ratio is 9/2 or 4 1/2 .
Hence , this is the required solution .
A convex polygon
Hope this helps :)
