Answer:
The diameter of the circle O is <em>12 units</em>
Step-by-step explanation:
There is no data in the image provided. To better help you, I'm assuming we have an arbitrary value of
and the triangle B0C is right
<u>Relations in the Circle</u>
The diameter (D) is twice the radius (r) and the radius is the distance measured from the center of the circle to any point of the circumference.
Since the triangle B0C has a right angle, BD is the hypotenuse and 0B=0C=r
Applying Pythagoras's theorem:
Thus we have
The diameter of the circle O is D=2(6) = 12 units
Answer:
See Explanation
Step-by-step explanation:
The question is not clear. However, I will treat the question as:
and:
Solving: and
Divide both sides by 26
Divide both sides by 50
Solving and
Express 1 as 2^0
Remove bracket
Cancel out 2
Divide both sides by 6
Express 1 as 5^0
Cancel out 5^0
1) 135 2) 119.40 if you still need the rest reply back to this answer
Answer:
Selling price of hockey game set is $145.32 , markup price is $210.54 and profit is $96 .
Step-by-step explanation:
Let us assume that the selling price of hockey game set be x .
As given
Pyotr Tchaikovsky Sporting Goods operates on a 45% overhead based on the selling price, which results in an overhead of $65.34 on the newest version of an air hockey game set.
45% is written in the decimal form .
= 0.45
Thus the equation becomes
0.45 × x = 65.34
0.45x = 65.34
x = 145.2
Therefore the selling price of the hockey game set is $145.2 .
Thus
Markup price = Selling price + Overhead Price
= $145.2 + $65.34
= $ 210.54
As given
If the air hockey game set costs Pyotr Tchaikovsky Sports $49.32 .
i.e Cost price of the hockey game set = $ 49.32
Profit = Selling price - Cost price
= 145.32 - 49.32
= $ 96
Therefore selling price of hockey game set is $145.32 , markup price is $210.54 and profit is $96 .
