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Andrei [34K]
3 years ago
11

Which is bigger 40% of 200 or 1/3 of 150

Mathematics
1 answer:
Gnesinka [82]3 years ago
3 0
First find out what 40% of 200 is
200 times .4 is 80

then find out what 1/3 of 150 is
divide 150 by three, which is 50
if it was 2/3 instead of 1/3, you would multiply 50 by 2

40% of 200 is greater
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The customer's change would be 3.32
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g Annual starting salaries in a certain region of the U. S. for college graduates with an engineering major are normally distrib
algol13

Answer:

The probability that the sample mean would be at least $39000 is of 0.8665 = 86.65%.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean $39725 and standard deviation $7320.

This means that \mu = 39725, \sigma = 7320

Sample of 125

This means that n = 125, s = \frac{7320}{\sqrt{125}}

The probability that the sample mean would be at least $39000 is about?

This is 1 subtracted by the pvalue of Z when X = 39000. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{39000 - 39725}{\frac{7320}{\sqrt{125}}}

Z = -1.11

Z = -1.11 has a pvalue of 0.1335

1 - 0.1335 = 0.8665

The probability that the sample mean would be at least $39000 is of 0.8665 = 86.65%.

4 0
2 years ago
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lbvjy [14]
-6x because this expression represents the product of a negative number (-6) and a variable (x).
4 0
3 years ago
How do you factor this so you can find the roots or what x equals?
Marina86 [1]
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Use synthetic division and you will see that 3 is a root:

3 | 1 -3 -3 11 -6
   |    3  0  -9  6
   ____________
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Use rational root again, to see that possible roots are: plus/minus 2,1

Try 2:

2 | 1 0 -3 -2
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   _____________
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The above is x^2+2x+1 which is a perfect square: (x+1)^2

So we have the final factorization: (x-3)(x-2)(x+1)^2

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Where -1 is a double zero.

6 0
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Whats ten ximes eight?
mart [117]

Answer:

80

Step-by-step explanation:

you have 8 ten times add 8 together ten times you get 80

6 0
3 years ago
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