Question

The sum of a number and 8 is no more than the square of the difference of the number and 4.

Answer 1

Let the number be x,
The sum of the number and 8 is
$(x + 8)$
The square of the difference of the number and 4 is
$(x - 4) {}^{2}$

Hence the inequality is
$(x + 8) \leqslant (x - 4) {}^{2}$


The correct answer is C